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How do we write the formulae of compounds and balance the equations that describe their reactions?

Writing formulae from ionic charges and oxidation states, constructing balanced chemical and ionic equations with state symbols, and using the language of chemistry consistently.

An Eduqas A-Level Chemistry C1.1 answer on writing formulae from ionic charges, constructing balanced full and ionic equations with state symbols, and the conventions of chemical language.

Generated by Claude Opus 4.810 min answer

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  1. What this topic is asking
  2. Writing formulae of ions and compounds
  3. Oxidation states as a formula tool
  4. Balancing chemical equations
  5. Ionic equations and spectator ions
  6. State symbols
  7. Examples in context
  8. Try this

What this topic is asking

Eduqas topic C1.1 wants you to write the formulae of elements, ions and compounds, deduce formulae from ionic charges and oxidation states, and construct balanced full and ionic equations with the correct state symbols. This is the grammar of chemistry: every later calculation and mechanism depends on getting it right.

Writing formulae of ions and compounds

The formula of a simple ion follows its position in the periodic table: Group 1 forms 1+1+ ions, Group 2 forms 2+2+, Group 6 forms 2βˆ’2- and Group 7 forms 1βˆ’1-. Transition metals and some non-metals form more than one ion, so their charge is shown by a Roman numeral, as in iron(II), Fe2+\text{Fe}^{2+}, and iron(III), Fe3+\text{Fe}^{3+}.

Oxidation states as a formula tool

The oxidation state (oxidation number) is the charge an atom would carry if all bonds were ionic. The rules give it directly: elements are 00, Group 1 is +1+1, Group 2 is +2+2, hydrogen is usually +1+1 (but βˆ’1-1 in metal hydrides), oxygen is usually βˆ’2-2 (but βˆ’1-1 in peroxides), and the sum equals the overall charge. Knowing that nitrogen is +5+5 in NO3βˆ’\text{NO}_3^- or chlorine is +5+5 in ClO3βˆ’\text{ClO}_3^- lets you build and name oxoanion formulae with confidence.

Balancing chemical equations

A balanced equation obeys conservation of mass: atoms are neither created nor destroyed.

Ionic equations and spectator ions

When ionic compounds react in solution, only some ions take part. An ionic equation shows just the species that change; the spectator ions, which are identical on both sides, are cancelled.

For neutralisation of any strong acid by any strong alkali, cancelling the spectators leaves the single ionic equation H+(aq)+OHβˆ’(aq)β†’H2O(l)\text{H}^+(\text{aq}) + \text{OH}^-(\text{aq}) \rightarrow \text{H}_2\text{O}(\text{l}), which is why all such reactions release a similar enthalpy of neutralisation.

State symbols

Every species in an Eduqas equation should carry a state symbol: (s)(\text{s}) solid, (l)(\text{l}) liquid, (g)(\text{g}) gas and (aq)(\text{aq}) aqueous (dissolved in water). Marks are routinely lost for omitting them or for writing a precipitate as (aq)(\text{aq}).

Examples in context

Example 1. Half-equations combine into a balanced redox equation. The displacement of copper by zinc is the sum of Zn(s)β†’Zn2+(aq)+2eβˆ’\text{Zn}(\text{s}) \rightarrow \text{Zn}^{2+}(\text{aq}) + 2\text{e}^- and Cu2+(aq)+2eβˆ’β†’Cu(s)\text{Cu}^{2+}(\text{aq}) + 2\text{e}^- \rightarrow \text{Cu}(\text{s}), giving Zn(s)+Cu2+(aq)β†’Zn2+(aq)+Cu(s)\text{Zn}(\text{s}) + \text{Cu}^{2+}(\text{aq}) \rightarrow \text{Zn}^{2+}(\text{aq}) + \text{Cu}(\text{s}). The electrons cancel because they appear equally on both sides, exactly like spectator ions.

Example 2. Naming guides the formula. "Iron(III) sulfate" tells you the cation is Fe3+\text{Fe}^{3+} and the anion is SO42βˆ’\text{SO}_4^{2-}; balancing the charges gives Fe2(SO4)3\text{Fe}_2(\text{SO}_4)_3. Reading the Roman numeral first prevents the most common formula error in inorganic questions.

Try this

Q1. Write the formula of ammonium carbonate. [1 mark]

  • Cue. Ammonium is NH4+\text{NH}_4^+ and carbonate is CO32βˆ’\text{CO}_3^{2-}, so two ammonium ions balance one carbonate: (NH4)2CO3(\text{NH}_4)_2\text{CO}_3.

Q2. Write the ionic equation, with state symbols, for adding dilute hydrochloric acid to solid calcium carbonate. [2 marks]

  • Cue. CaCO3(s)+2H+(aq)β†’Ca2+(aq)+H2O(l)+CO2(g)\text{CaCO}_3(\text{s}) + 2\text{H}^+(\text{aq}) \rightarrow \text{Ca}^{2+}(\text{aq}) + \text{H}_2\text{O}(\text{l}) + \text{CO}_2(\text{g}). Chloride is the spectator ion.

Exam-style practice questions

Practice questions written in the style of WJEC Eduqas exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Eduqas 20194 marks(a) Write the formula of aluminium sulfate. (b) Write a balanced symbol equation, including state symbols, for the reaction of solid magnesium carbonate with dilute nitric acid.
Show worked answer β†’

(a) Aluminium is Al3+\text{Al}^{3+} and sulfate is SO42βˆ’\text{SO}_4^{2-}. Balancing the charges needs two Al3+\text{Al}^{3+} to three SO42βˆ’\text{SO}_4^{2-}, giving Al2(SO4)3\text{Al}_2(\text{SO}_4)_3 (1).

(b) MgCO3(s)+2HNO3(aq)β†’Mg(NO3)2(aq)+H2O(l)+CO2(g)\text{MgCO}_3(\text{s}) + 2\text{HNO}_3(\text{aq}) \rightarrow \text{Mg(NO}_3)_2(\text{aq}) + \text{H}_2\text{O}(\text{l}) + \text{CO}_2(\text{g}).

Markers reward the correct formula of the salt Mg(NO3)2\text{Mg(NO}_3)_2 (1), the balanced equation (1) and correct state symbols throughout (1).

Eduqas 20213 marksWhen silver nitrate solution is added to sodium chloride solution, a white precipitate of silver chloride forms. Write the ionic equation for this reaction, including state symbols, and explain why sodium and nitrate ions do not appear in it.
Show worked answer β†’

Ionic equation: Ag+(aq)+Clβˆ’(aq)β†’AgCl(s)\text{Ag}^+(\text{aq}) + \text{Cl}^-(\text{aq}) \rightarrow \text{AgCl}(\text{s}) (2: 1 for species, 1 for state symbols).

Sodium ions (Na+\text{Na}^+) and nitrate ions (NO3βˆ’\text{NO}_3^-) are spectator ions: they are present in solution before and after the reaction and are not changed, so they cancel from the full equation and are omitted (1).

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