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What determines the resistance of a component?

Ohm's law, I-V characteristics of ohmic and non-ohmic components, resistivity ρ=RA/L\rho = RA/L, and the variation of resistance with temperature for metals and semiconductors.

A focused answer to the Edexcel 9PH0 resistance content, covering Ohm's law, I-V characteristics of a metallic conductor, filament lamp and diode, resistivity ρ=RA/L\rho = RA/L, and temperature dependence in metals and semiconductors.

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  1. What this dot point is asking
  2. The answer
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What this dot point is asking

Edexcel wants you to state Ohm's law and recognise when it applies, sketch and explain the current-voltage (I-V) characteristics of a metallic conductor, a filament lamp and a semiconductor diode, define and use resistivity through R=ρLAR = \frac{\rho L}{A}, and explain why the resistance of a metal rises with temperature while that of a semiconductor (and a thermistor) falls.

The answer

Ohm's law and resistance

A component that obeys Ohm's law over the range tested is ohmic and has a constant resistance, giving a straight-line I-V graph through the origin. Resistance always equals V/IV/I at any point on the graph, but only an ohmic component has a single constant value across the whole range.

I-V characteristics

The diode is strongly non-ohmic and non-symmetric: it acts almost as an open circuit in reverse bias and as a low resistance once the forward voltage exceeds the threshold. When plotting characteristics experimentally, swap the supply connections to reach negative voltages, and use a potentiometer divider so you can vary the voltage smoothly down to zero.

Resistivity

Resistivity is a property of the material itself, independent of the sample's shape, which lets you compare conductors fairly. Copper has a low resistivity (about 1.7×1081.7 \times 10^{-8} ohm metre), which is why it is used for wiring; nichrome has a much higher resistivity and is used for heating elements.

Required practical: measuring resistivity

Measure the wire's diameter at several points with a micrometer (take the mean and halve it for the radius, then A=πr2A = \pi r^2). Measure resistance for several lengths using an ammeter and voltmeter, plot RR against LL, and use the gradient ρA\frac{\rho}{A} to find ρ=gradient×A\rho = \text{gradient} \times A. Keep the current low so the wire does not heat up and change its resistance.

Temperature dependence

In a pure metal, raising the temperature makes the lattice ions vibrate with greater amplitude, so conduction electrons collide with them more frequently; the resistance rises roughly linearly over normal ranges. In an intrinsic semiconductor, raising the temperature liberates many more charge carriers (electrons and holes), and this huge increase in carrier number outweighs the increased scattering, so the resistance falls sharply. This is why a thermistor is used as a temperature sensor.

Examples in context

National Grid transmission cables use thick aluminium or copper to keep ρL/A\rho L / A and hence resistive heating losses low. A toaster element is made of high-resistivity nichrome so a short, robust wire reaches red heat. A platinum resistance thermometer exploits the near-linear rise of metallic resistance with temperature for precise measurement, while an NTC thermistor exploits the opposite semiconductor behaviour to sense overheating in electronics and engines.

Try this

Q1. State Ohm's law. [1 mark]

  • Cue. At constant temperature, the current through a metallic conductor is directly proportional to the potential difference across it.

Q2. A wire of resistivity 5.0×1075.0 \times 10^{-7} ohm metre, length 2.02.0 m and area 1.0×1061.0 \times 10^{-6} m squared. Find its resistance. [2 marks]

  • Cue. R=ρLA=5.0×107×2.01.0×106=1.0R = \frac{\rho L}{A} = \frac{5.0 \times 10^{-7} \times 2.0}{1.0 \times 10^{-6}} = 1.0 ohm.

Q3. Explain why the resistance of a metal increases with temperature. [2 marks]

  • Cue. The lattice ions vibrate more, scattering conduction electrons more frequently, so the resistance rises.

Exam-style practice questions

Practice questions written in the style of Pearson Edexcel exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Edexcel 20174 marksA wire of length 1.51.5 m and cross-sectional area 2.0×1072.0 \times 10^{-7} m squared has a resistance of 3.63.6 ohm. Calculate the resistivity of the metal.
Show worked answer →

Resistivity is defined by R=ρLAR = \frac{\rho L}{A}, so ρ=RAL\rho = \frac{RA}{L}.

ρ=3.6×2.0×1071.5=7.2×1071.5=4.8×107\rho = \frac{3.6 \times 2.0 \times 10^{-7}}{1.5} = \frac{7.2 \times 10^{-7}}{1.5} = 4.8 \times 10^{-7} ohm metre.

Markers reward correct rearrangement, substitution with consistent SI units, and the unit ohm metre.

Edexcel 20204 marksSketch and explain the I-V characteristic of a filament lamp.
Show worked answer →

The graph is an S-shaped curve through the origin, symmetrical about the origin: at low voltages it is nearly a straight line (ohmic), but as the current rises the curve bends towards the voltage axis so that the gradient (the current per unit voltage) decreases.

Explanation: as current increases, the filament heats up; in a metal the lattice ions vibrate more and scatter the conduction electrons more often, so the resistance rises. A higher resistance means a smaller increase in current for each extra volt, giving the flattening curve.

Markers reward the correct shape (through the origin, symmetric, bending towards the V-axis) and the temperature-resistance reasoning.

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