How do the types of bonding and structure explain the physical properties of substances?
Ionic, covalent (including dative) and metallic bonding, electronegativity and bond polarity, the shapes of simple molecules and ions, and the four types of crystal structure.
An Edexcel 9CH0 Topic 2 answer covering ionic, covalent, dative and metallic bonding, electronegativity and polarity, molecular shapes from electron-pair repulsion, and the four crystal structures.
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What this topic is asking
Edexcel Topic 2 wants you to classify bonding as ionic, covalent (including dative), or metallic, use electronegativity to judge bond polarity, predict molecular and ionic shapes using electron-pair repulsion theory, and relate the four crystal structures to physical properties.
The answer
The three bond types
Electronegativity and polarity
Electronegativity is the ability of an atom to attract the bonding electrons in a covalent bond. A difference in electronegativity makes a bond polar, giving a permanent dipole. A molecule can contain polar bonds yet be non-polar overall if the dipoles cancel by symmetry, as in .
Shapes of molecules
Electron pairs in the outer shell repel and arrange themselves as far apart as possible. Lone pairs repel more strongly than bonding pairs, reducing bond angles by about each.
The four crystal structures
- Giant ionic (e.g. ): high melting point, conducts when molten or dissolved.
- Giant covalent (e.g. diamond, graphite, ): very high melting point; graphite conducts due to delocalised electrons.
- Simple molecular (e.g. , ice): low melting point, weak intermolecular forces, non-conductor.
- Metallic: good conductor, malleable, melting point depends on charge and ion size.
The link to properties is the marking point: melting points reflect the strength of the bonds or forces that must be overcome, and electrical conduction needs mobile charge carriers (ions in molten ionic compounds, delocalised electrons in metals and graphite).
Examples in context
Example 1. Why diamond tips drill bits. Diamond is a giant covalent structure in which every carbon is bonded to four others by strong covalent bonds in a rigid three-dimensional lattice. Breaking it requires breaking many strong bonds, which is why diamond is the hardest natural material and is used on drill bits and saw blades. Graphite, by contrast, has layers held together only by weak forces, so it flakes and is used as a lubricant and in pencils, a vivid demonstration that structure, not just composition, controls properties.
Example 2. Alloys and why they are harder than pure metals. Pure metals are malleable because layers of identical ions slide over one another. Alloys such as steel contain atoms of different sizes that disrupt the regular layers, so the layers cannot slide as easily and the alloy is harder. This explains why bronze, brass and steel are used in tools and structures rather than the soft pure metals, applying the metallic-bonding model from Topic 2.
Try this
Q1. State and explain the shape and bond angle of an ammonia molecule. [3 marks]
- Cue. Pyramidal, ; three bonding pairs and one lone pair, and the lone pair repels more, reducing the angle from .
Q2. Explain why magnesium oxide has a higher melting point than sodium chloride. [2 marks]
- Cue. and carry higher charges than and , so stronger electrostatic attraction in the lattice.
Exam-style practice questions
Practice questions written in the style of Pearson Edexcel exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.
Edexcel 20195 marks(a) Predict and explain the shape and bond angle of and of . (b) Explain why is non-polar even though the bonds are polar.Show worked answer β
Apply electron-pair repulsion, then use symmetry for polarity.
(a) has three bonding pairs and no lone pairs, so the shape is trigonal planar with bond angles of (1) (1). has three bonding pairs and one lone pair; the lone pair repels more, so the shape is pyramidal with a bond angle of (1) (1).
(b) In the three polar bond dipoles are arranged symmetrically at and cancel exactly, so the molecule has no overall dipole and is non-polar (1).
Edexcel 20214 marksExplain, in terms of structure and bonding, why (a) sodium chloride conducts electricity when molten but not when solid, and (b) graphite conducts electricity but diamond does not.Show worked answer β
Link conduction to the availability of mobile charge carriers.
(a) Sodium chloride is a giant ionic lattice. When solid, the ions are fixed in the lattice and cannot move (1); when molten, the ions are free to move and carry charge (1).
(b) Graphite has delocalised electrons (each carbon bonds to only three others), which are free to move along the layers and carry charge (1). In diamond every carbon is bonded to four others with no spare delocalised electrons, so there are no mobile charge carriers and it does not conduct (1).
Related dot points
- Sub-atomic particles, isotopes and mass spectrometry, electronic configuration in sub-shells, ionisation energies and the evidence they provide for shell and sub-shell structure.
An Edexcel 9CH0 Topic 1 answer covering protons, neutrons and electrons, isotopes and mass spectrometry, electron configuration in sub-shells, and the ionisation energy evidence for shell structure.
- London (dispersion) forces, permanent dipole-dipole forces and hydrogen bonding, how they arise, and how they explain boiling points, solubility and the anomalous properties of water.
An Edexcel 9CH0 Topic 8 answer covering London forces, permanent dipole-dipole forces and hydrogen bonding, and how they explain boiling points, solubility and the properties of water.
- Periodicity in ionisation energy and physical properties, the reactions and trends of Group 2 (the alkaline earth metals) and Group 7 (the halogens), and the chemical tests that identify them.
An Edexcel 9CH0 Topic 4 answer covering periodicity, the trends and reactions of Group 2 and Group 7, halide ion tests, and the explanations behind the patterns.
- The mole and the Avogadro constant, empirical and molecular formulae, balanced equations, the ideal gas equation, concentration and titration calculations, percentage yield and atom economy.
An Edexcel 9CH0 Topic 5 answer covering the mole, empirical and molecular formulae, balanced equations, the ideal gas equation, concentration and titrations, percentage yield and atom economy.
- Oxidation numbers, oxidation and reduction as electron transfer, oxidising and reducing agents, ionic half-equations and the construction of balanced redox equations including disproportionation.
An Edexcel 9CH0 Topic 3 answer covering oxidation numbers, oxidation and reduction as electron transfer, oxidising and reducing agents, half-equations, and disproportionation.
Sources & how we know this
- Pearson Edexcel A-Level Chemistry (9CH0) specification β Pearson Edexcel (2015)