Skip to main content
EnglandBiologySyllabus dot point

How do cells release energy from glucose in aerobic and anaerobic respiration?

The stages of aerobic respiration (glycolysis, the link reaction, the Krebs cycle and oxidative phosphorylation), the role of ATP and the mitochondrion, and anaerobic respiration in animals and yeast.

An Edexcel A-Level Biology B (Salters-Nuffield) answer on respiration, covering glycolysis, the link reaction, the Krebs cycle and oxidative phosphorylation, the role of ATP and the mitochondrion, and anaerobic respiration in animals and yeast.

Generated by Claude Opus 4.810 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

Have a quick question? Jump to the Q&A page

Jump to a section
  1. What this dot point is asking
  2. ATP and the mitochondrion
  3. The stages of aerobic respiration
  4. Anaerobic respiration
  5. Examples in context
  6. Try this

What this dot point is asking

Edexcel wants you to describe the four stages of aerobic respiration, explain the role of ATP and the mitochondrion, and describe anaerobic respiration in animals and yeast. Questions often centre on oxidative phosphorylation and on comparing aerobic with anaerobic ATP yields.

ATP and the mitochondrion

The stages of aerobic respiration

Taking the stages in turn helps you keep them straight:

  • Glycolysis does not need oxygen. Glucose (6 carbons) is first phosphorylated using 2 ATP, then split and oxidised into two molecules of pyruvate (3 carbons each). This makes 4 ATP (so a net gain of 2) and reduces 2 NAD to reduced NAD.
  • Link reaction. Each pyruvate enters the mitochondrial matrix and is decarboxylated (losing carbon dioxide) and oxidised (reducing NAD) to form a 2-carbon acetyl group, which joins coenzyme A to make acetyl coenzyme A.
  • Krebs cycle. Acetyl coenzyme A combines with a 4-carbon compound to form a 6-carbon compound (citrate). Through the cycle, carbon dioxide is released, NAD and FAD are reduced and a little ATP is made by substrate-level phosphorylation. The cycle turns twice per glucose.
  • Oxidative phosphorylation. The reduced NAD and reduced FAD donate electrons to the electron transport chain on the cristae; the energy released pumps protons to make a gradient, and protons flowing back through ATP synthase make most of the ATP. Oxygen accepts the spent electrons and protons to form water.

Anaerobic respiration

When oxygen is unavailable, only glycolysis can continue. To keep glycolysis going, the reduced NAD must be reoxidised.

  • In animals: pyruvate is converted to lactate. This regenerates NAD but the lactate must later be broken down.
  • In yeast and plants: pyruvate is converted to ethanol and carbon dioxide (fermentation).

Anaerobic respiration releases far less ATP than aerobic respiration (a net 22 ATP from glycolysis, against roughly 3838 aerobically) because the Krebs cycle and oxidative phosphorylation do not run. The reduced NAD must be reoxidised by passing its hydrogen to pyruvate, otherwise glycolysis would halt for lack of NAD.

Examples in context

Example 1. The oxygen debt after sprinting. During a sprint, muscles respire anaerobically because oxygen cannot be delivered fast enough, producing lactate. After the sprint, the runner keeps breathing hard to take in extra oxygen (the oxygen debt or excess post-exercise oxygen consumption) to oxidise the lactate back to pyruvate, which is then respired aerobically or converted to glucose in the liver. This links respiration to the muscle and exercise topics.

Example 2. Yeast in brewing and baking. Yeast respiring anaerobically converts sugars to ethanol and carbon dioxide. Brewers use the ethanol; bakers use the carbon dioxide to make bread rise. The same fermentation pathway has two commercial uses, a common applied context, and contrasts with the lactate pathway in animals.

Try this

Q1. State where glycolysis takes place and one product it makes. [2 marks]

  • Cue. In the cytoplasm; it produces pyruvate (and a net 2 ATP and reduced NAD).

Q2. Explain why anaerobic respiration releases less ATP than aerobic respiration. [2 marks]

  • Cue. Only glycolysis runs; the Krebs cycle and oxidative phosphorylation, which produce most of the ATP, do not occur.

Exam-style practice questions

Practice questions written in the style of Pearson Edexcel exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Edexcel 20196 marksDescribe the role of the inner mitochondrial membrane in oxidative phosphorylation and explain how it produces most of the ATP in aerobic respiration.
Show worked answer →

Markers want the chemiosmotic mechanism on the cristae.

Reduced NAD and reduced FAD from glycolysis, the link reaction and the Krebs cycle are oxidised, releasing electrons that pass along the electron transport chain embedded in the inner membrane (cristae). As electrons pass along, energy is used to pump protons from the matrix into the intermembrane space, creating a proton gradient (a higher proton concentration outside the matrix). Protons then diffuse back into the matrix through ATP synthase, and this flow provides the energy to phosphorylate ADP to ATP (chemiosmosis). Oxygen is the final electron acceptor, combining with electrons and protons to form water, which keeps the chain running. The folded cristae give a large surface area for many electron transport chains, so most of the ATP (around 3434 molecules per glucose) is made here.

Award marks for: reduced coenzymes donate electrons to the chain; electrons release energy to pump protons; proton gradient formed; protons flow through ATP synthase making ATP; oxygen final electron acceptor forms water; cristae give large surface area.

Edexcel 20214 marksAerobic respiration of one glucose molecule yields about 3838 ATP, while anaerobic respiration in a muscle yields only 22 ATP. Calculate the percentage of the aerobic yield that anaerobic respiration provides, and explain the difference.
Show worked answer →

A short calculation plus explanation.

Percentage =238×100=5.3%= \frac{2}{38} \times 100 = 5.3\% (to 2 significant figures). The difference arises because in anaerobic respiration only glycolysis runs, giving a net 22 ATP. The link reaction, Krebs cycle and oxidative phosphorylation do not occur because there is no oxygen to act as the final electron acceptor, so the large amount of ATP normally made on the inner mitochondrial membrane is not produced. Pyruvate is instead converted to lactate to regenerate NAD so glycolysis can continue.

Markers reward: correct 5.3%5.3\%; only glycolysis runs anaerobically; no oxygen so oxidative phosphorylation stops; lactate regenerates NAD.

Related dot points

Sources & how we know this