How do cells release energy from glucose in aerobic and anaerobic respiration?
The stages of aerobic respiration (glycolysis, the link reaction, the Krebs cycle and oxidative phosphorylation), the role of ATP and the mitochondrion, and anaerobic respiration in animals and yeast.
An Edexcel A-Level Biology B (Salters-Nuffield) answer on respiration, covering glycolysis, the link reaction, the Krebs cycle and oxidative phosphorylation, the role of ATP and the mitochondrion, and anaerobic respiration in animals and yeast.
Reviewed by: AI editorial process; not yet individually human-reviewed
Have a quick question? Jump to the Q&A page
Jump to a section
What this dot point is asking
Edexcel wants you to describe the four stages of aerobic respiration, explain the role of ATP and the mitochondrion, and describe anaerobic respiration in animals and yeast. Questions often centre on oxidative phosphorylation and on comparing aerobic with anaerobic ATP yields.
ATP and the mitochondrion
The stages of aerobic respiration
Taking the stages in turn helps you keep them straight:
- Glycolysis does not need oxygen. Glucose (6 carbons) is first phosphorylated using 2 ATP, then split and oxidised into two molecules of pyruvate (3 carbons each). This makes 4 ATP (so a net gain of 2) and reduces 2 NAD to reduced NAD.
- Link reaction. Each pyruvate enters the mitochondrial matrix and is decarboxylated (losing carbon dioxide) and oxidised (reducing NAD) to form a 2-carbon acetyl group, which joins coenzyme A to make acetyl coenzyme A.
- Krebs cycle. Acetyl coenzyme A combines with a 4-carbon compound to form a 6-carbon compound (citrate). Through the cycle, carbon dioxide is released, NAD and FAD are reduced and a little ATP is made by substrate-level phosphorylation. The cycle turns twice per glucose.
- Oxidative phosphorylation. The reduced NAD and reduced FAD donate electrons to the electron transport chain on the cristae; the energy released pumps protons to make a gradient, and protons flowing back through ATP synthase make most of the ATP. Oxygen accepts the spent electrons and protons to form water.
Anaerobic respiration
When oxygen is unavailable, only glycolysis can continue. To keep glycolysis going, the reduced NAD must be reoxidised.
- In animals: pyruvate is converted to lactate. This regenerates NAD but the lactate must later be broken down.
- In yeast and plants: pyruvate is converted to ethanol and carbon dioxide (fermentation).
Anaerobic respiration releases far less ATP than aerobic respiration (a net ATP from glycolysis, against roughly aerobically) because the Krebs cycle and oxidative phosphorylation do not run. The reduced NAD must be reoxidised by passing its hydrogen to pyruvate, otherwise glycolysis would halt for lack of NAD.
Examples in context
Example 1. The oxygen debt after sprinting. During a sprint, muscles respire anaerobically because oxygen cannot be delivered fast enough, producing lactate. After the sprint, the runner keeps breathing hard to take in extra oxygen (the oxygen debt or excess post-exercise oxygen consumption) to oxidise the lactate back to pyruvate, which is then respired aerobically or converted to glucose in the liver. This links respiration to the muscle and exercise topics.
Example 2. Yeast in brewing and baking. Yeast respiring anaerobically converts sugars to ethanol and carbon dioxide. Brewers use the ethanol; bakers use the carbon dioxide to make bread rise. The same fermentation pathway has two commercial uses, a common applied context, and contrasts with the lactate pathway in animals.
Try this
Q1. State where glycolysis takes place and one product it makes. [2 marks]
- Cue. In the cytoplasm; it produces pyruvate (and a net 2 ATP and reduced NAD).
Q2. Explain why anaerobic respiration releases less ATP than aerobic respiration. [2 marks]
- Cue. Only glycolysis runs; the Krebs cycle and oxidative phosphorylation, which produce most of the ATP, do not occur.
Exam-style practice questions
Practice questions written in the style of Pearson Edexcel exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.
Edexcel 20196 marksDescribe the role of the inner mitochondrial membrane in oxidative phosphorylation and explain how it produces most of the ATP in aerobic respiration.Show worked answer →
Markers want the chemiosmotic mechanism on the cristae.
Reduced NAD and reduced FAD from glycolysis, the link reaction and the Krebs cycle are oxidised, releasing electrons that pass along the electron transport chain embedded in the inner membrane (cristae). As electrons pass along, energy is used to pump protons from the matrix into the intermembrane space, creating a proton gradient (a higher proton concentration outside the matrix). Protons then diffuse back into the matrix through ATP synthase, and this flow provides the energy to phosphorylate ADP to ATP (chemiosmosis). Oxygen is the final electron acceptor, combining with electrons and protons to form water, which keeps the chain running. The folded cristae give a large surface area for many electron transport chains, so most of the ATP (around molecules per glucose) is made here.
Award marks for: reduced coenzymes donate electrons to the chain; electrons release energy to pump protons; proton gradient formed; protons flow through ATP synthase making ATP; oxygen final electron acceptor forms water; cristae give large surface area.
Edexcel 20214 marksAerobic respiration of one glucose molecule yields about ATP, while anaerobic respiration in a muscle yields only ATP. Calculate the percentage of the aerobic yield that anaerobic respiration provides, and explain the difference.Show worked answer →
A short calculation plus explanation.
Percentage (to 2 significant figures). The difference arises because in anaerobic respiration only glycolysis runs, giving a net ATP. The link reaction, Krebs cycle and oxidative phosphorylation do not occur because there is no oxygen to act as the final electron acceptor, so the large amount of ATP normally made on the inner mitochondrial membrane is not produced. Pyruvate is instead converted to lactate to regenerate NAD so glycolysis can continue.
Markers reward: correct ; only glycolysis runs anaerobically; no oxygen so oxidative phosphorylation stops; lactate regenerates NAD.
Related dot points
- The light-dependent and light-independent reactions of photosynthesis, the role of chloroplast structure, the products of each stage, and the factors that limit the rate of photosynthesis.
An Edexcel A-Level Biology B (Salters-Nuffield) answer on photosynthesis, covering the light-dependent and light-independent reactions, the structure of the chloroplast, the role of ATP and NADP, and limiting factors.
- The structure of skeletal muscle and the sliding filament model of contraction, the role of ATP and calcium ions, and the difference between slow and fast twitch fibres.
An Edexcel A-Level Biology B (Salters-Nuffield) answer on muscles and movement, covering skeletal muscle structure, the sliding filament model, the role of ATP and calcium ions in contraction, and slow and fast twitch fibres.
- The structure of a neurone and the transmission of a nerve impulse, the events at a synapse, the action of hormones, and the differences between nervous and hormonal coordination.
An Edexcel A-Level Biology B (Salters-Nuffield) answer on nervous and hormonal coordination, covering neurone structure, the resting potential and action potential, synaptic transmission, the action of hormones, and how nervous and hormonal coordination differ.
- The principle of homeostasis and negative feedback, the control of body temperature and blood glucose, and the structure and function of the kidney in osmoregulation and excretion.
An Edexcel A-Level Biology B (Salters-Nuffield) answer on homeostasis and the kidney, covering negative feedback, the control of temperature and blood glucose, and the structure and function of the kidney in excretion and osmoregulation.
- Enzymes as biological catalysts, the lock-and-key and induced-fit models, the effects of temperature, pH, substrate and enzyme concentration on rate, and the action of inhibitors.
An Edexcel A-Level Biology B answer on enzymes as catalysts, the lock-and-key and induced-fit models, factors affecting rate, and competitive and non-competitive inhibition.
Sources & how we know this
- Pearson Edexcel A-Level Biology B (9BN0) specification — Pearson Edexcel (2015)