AQA A-Level Physics 3.7 Fields and their consequences overview quiz quiz

The sum of the two masses and directly proportional to the square of their separation distance

The product of the masses and inversely proportional to the separation, not its square

The product of the masses and inversely proportional to the square of the separation

The difference between the two masses and inversely proportional to the cube of the separation

Because the gravitational force between two masses is fundamentally a repulsive one, not attractive

Because mass is always a positive quantity and so the potential it produces must also be positive

Because the potential gradient is exactly zero everywhere within a uniform gravitational field

Because the field is attractive, so work is released as a mass moves inward

The gravitational attraction of the planet

Air resistance acting on the satellite as it moves through the upper atmosphere

The continuous forward thrust produced by the satellite's own onboard engines

A magnetic force arising from the interaction with the planet's magnetic field

It has a period of exactly 12 hours and passes directly over both of the Earth's poles each orbit

It has a period of 24 hours over the equator, staying above one fixed point

It orbits the Earth at exactly the same height above the surface as the Moon does in its own orbit

It travels from east to west and moves much faster around its orbit than the Earth itself rotates

$4.8 \times 10^{-1}$ V/m

$30$ V/m

$3.0 \times 10^4$ V/m

$480$ V/m

$2.0 \times 10^{-3}$ J

$1.0 \times 10^{-3}$ J

$2.0$ J

$1.0 \times 10^{-2}$ J

37 percent

50 percent

63 percent

10 percent

$F = \frac{Bq}{v}$

$F = Bqv$

$F = \frac{q}{Bv}$

$F = Bq$

Faraday's law

Coulomb's law

Lenz's law

Kepler's law

To increase the current flowing in the cables and so increase the total power delivered to homes

Because step-up and step-down transformers are only able to operate at very high voltages at all

Purely to allow the transmission cables to be made thinner and therefore cheaper to manufacture

To reduce the current so that $I^2R$ heating losses in the cables are smaller

$100$ V

$4$ V

$25$ V

$500$ V

It is directly proportional to the distance $r$ from the centre of the mass

It is proportional to $\frac{1}{r^2}$

It is inversely proportional to the distance $r$ but not to its square

It is constant and does not change at all with distance $r$