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What is an atom made of, and how do we measure and arrange its particles?

Fundamental particles (protons, neutrons, electrons), mass number and atomic number, isotopes, the time of flight (TOF) mass spectrometer, relative atomic mass, electron configuration in sub-shells, and the trends in ionisation energy across periods and down groups.

A focused answer to AQA A-Level Chemistry 3.1.1, covering the fundamental particles, isotopes, the time of flight mass spectrometer, relative atomic mass, sub-shell electron configuration and ionisation energy trends.

Generated by Claude Opus 4.810 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this dot point is asking
  2. The fundamental particles
  3. The time of flight (TOF) mass spectrometer
  4. Relative atomic mass
  5. Electron configuration and ionisation energy

What this dot point is asking

AQA wants you to know the properties of the fundamental particles, define mass number, atomic number and isotopes, describe how a time of flight mass spectrometer works, calculate relative atomic mass from isotopic data, write electron configurations in sub-shells, and explain ionisation energy trends.

The fundamental particles

The time of flight (TOF) mass spectrometer

Four stages:

  1. Ionisation. In electrospray ionisation the sample is dissolved in a volatile solvent and pushed through a fine needle at high voltage; each molecule gains a proton to form XH+\text{X}\text{H}^+ (so the recorded mass is Mr+1M_r + 1). In electron impact ionisation the sample is vaporised and bombarded with high-energy electrons that knock one electron out to form X+\text{X}^+ (often fragmenting larger molecules).
  2. Acceleration. The positive ions are accelerated through an electric field so that every ion of charge +1+1 gains the same kinetic energy. Because KE=12mv2KE = \tfrac{1}{2}mv^2 is fixed, heavier ions end up moving more slowly.
  3. Ion drift. The ions pass through a field-free flight tube of fixed length. Lighter ions reach the detector first; the time of flight tt is proportional to m\sqrt{m}.
  4. Detection. Each ion gains an electron at the detector, generating a current; the size of the current measures abundance, and the flight time gives the mass-to-charge ratio mz\frac{m}{z}.

Because all ions are accelerated to the same kinetic energy, 12mv2=constant\tfrac{1}{2}mv^2 = \text{constant}, so the flight time over a fixed distance directly encodes the mass. This is why a TOF instrument can resolve isotopes that differ by a single mass unit.

Relative atomic mass

The relative atomic mass is the weighted mean of the isotope masses, weighted by abundance. The same idea gives relative isotopic abundance from a mass spectrum, where each peak height is proportional to the abundance of that isotope.

Electron configuration and ionisation energy

Electrons fill sub-shells in order of increasing energy: 1s 2s 2p 3s 3p 4s 3d 4p1s\ 2s\ 2p\ 3s\ 3p\ 4s\ 3d\ 4p. The 4s4s sub-shell is slightly lower in energy than 3d3d, so it fills before 3d3d but, because it is the outermost, it empties first when the atom ionises (so Fe2+\text{Fe}^{2+} is [Ar]3d6[\text{Ar}]3d^6, not [Ar]4s23d4[\text{Ar}]4s^2 3d^4). Each ss sub-shell holds 2 electrons, each pp holds 6 and each dd holds 10, and within a sub-shell orbitals are singly filled before pairing (Hund's rule).

The first ionisation energy is the energy to remove one mole of electrons from one mole of gaseous atoms to form one mole of gaseous +1+1 ions: X(g)X+(g)+e\text{X(g)} \rightarrow \text{X}^+\text{(g)} + \text{e}^-. It depends on nuclear charge, atomic radius and shielding. It rises across a period (greater nuclear charge pulls the same shell in, smaller radius, similar shielding) and falls down a group (extra inner shells mean more shielding and a larger radius, so the outer electron is held less tightly). Successive ionisation energies always increase, and a large jump between two successive values reveals a change of shell, which is how the group of an element can be deduced.

Exam-style practice questions

Practice questions written in the style of AQA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

AQA 20184 marksExplain the general increase in first ionisation energy across Period 3 from sodium to argon, and account for the dip at aluminium and at sulfur.
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Across the period the nuclear charge increases while electrons are added to the same shell, so the atomic radius decreases and shielding stays roughly constant. The outer electrons are held more strongly, so first ionisation energy generally rises.

The dip at aluminium occurs because its outer electron is in a 3p3p sub-shell, which is higher in energy (and slightly shielded by the 3s3s pair) than the 3s3s electron removed from magnesium, so it is easier to remove. The dip at sulfur occurs because its 3p3p sub-shell has a pair of electrons in one orbital; the electron-electron repulsion within that pair makes one easier to remove than the single electron in phosphorus.

Markers reward the trend (nuclear charge, radius, shielding) plus both the sub-shell argument for aluminium and the spin-pair repulsion argument for sulfur.

AQA 20203 marksMagnesium has three isotopes. A sample contains Mg-24\text{Mg-24} (78.99%78.99\%), Mg-25\text{Mg-25} (10.00%10.00\%) and Mg-26\text{Mg-26} (11.01%11.01\%). Calculate the relative atomic mass of magnesium to two decimal places.
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Multiply each isotope mass by its percentage abundance and divide by 100 (the abundances already sum to 100):

Ar=(24×78.99)+(25×10.00)+(26×11.01)100A_r = \frac{(24 \times 78.99) + (25 \times 10.00) + (26 \times 11.01)}{100}.

The numerator is 1895.76+250.0+286.26=2432.021895.76 + 250.0 + 286.26 = 2432.02, so Ar=24.32A_r = 24.32.

Markers reward the weighted-mean method, correct arithmetic, and an answer of 24.3224.32 given to two decimal places.

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