AQA A-Level Chemistry 3.1 Physical chemistry overview quiz quiz

Concentration

Pressure

Temperature

Adding a catalyst

The reaction is endothermic and absorbs heat from the surroundings

The reaction cannot occur because a negative value is not allowed

The products are higher in energy than the reactants in this reaction

The reaction is exothermic and releases heat to the surroundings

It provides an alternative pathway with a lower activation energy

It increases the activation energy needed for the reaction to proceed

It raises the temperature of the reactants so more collisions succeed

It shifts the position of equilibrium to the right to favour products

$+3$

$+5$

$-3$

$+6$

$0.25$ K

$3600$ K

$250$ K

$25$ K

$K_p = \frac{(p_{SO_2})^2 (p_{O_2})}{(p_{SO_3})^2}$

$K_p = \frac{p_{SO_3}}{p_{SO_2} \, p_{O_2}}$

$K_p = (p_{SO_3})^2 (p_{SO_2})^2 (p_{O_2})$

$K_p = \frac{(p_{SO_3})^2}{(p_{SO_2})^2 (p_{O_2})}$

$1.0$

$2.0$

$3.0$

$12.0$

Third order

First order

Second order

Zero order

The more negative electrode potential minus the more positive electrode potential

The sum of the two standard electrode potentials added together directly

The more positive electrode potential minus the more negative electrode potential

The product of the two standard electrode potentials multiplied together

The curve starts above the origin because every molecule has some energy

The curve meets and touches the x-axis again at very high energies

Raising the temperature shifts the whole curve towards the left

The area under the curve equals the total number of molecules

$1.0 \times 10^{-14}$ mol$^2$ dm$^{-6}$

$1.0 \times 10^{-7}$ mol$^2$ dm$^{-6}$

$7.00 \times 10^{0}$ mol$^2$ dm$^{-6}$

$1.0 \times 10^{-14}$ mol$^4$ dm$^{-12}$

An oxidising agent

A reducing agent

A catalyst

A buffer