Skip to main content
WalesMathsSyllabus dot point

How do you work out percentage change, reverse percentages, and simple and compound interest in real-life financial contexts?

Calculate percentage increase and decrease, percentage change and reverse percentages, and solve financial problems involving simple interest, compound interest and repeated percentage change.

A focused answer to the WJEC GCSE Mathematics number content on percentages and financial mathematics, covering percentage change, reverse percentages, simple and compound interest, and repeated percentage change in real-life money contexts.

Generated by Claude Opus 4.812 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

Have a quick question? Jump to the Q&A page

Jump to a section
  1. What this dot point is asking
  2. Percentage increase and decrease
  3. Percentage change and reverse percentages
  4. Simple and compound interest
  5. Everyday financial contexts
  6. Depreciation and repeated change
  7. Why this matters

What this dot point is asking

WJEC places real financial mathematics at the heart of its number content, reflecting the strong everyday-money focus of the Welsh specification. You must calculate percentage increase and decrease, find a percentage change, work backwards through reverse percentages, and handle simple interest, compound interest and repeated percentage change. These appear mostly on the calculator Unit 2 and in worded, real-life contexts such as savings, sales, depreciation and bills, so a confident multiplier method is the key skill.

Percentage increase and decrease

The fastest method is a single decimal multiplier rather than finding the percentage and adding it on separately.

This multiplier method is faster, less error-prone, and extends straight to repeated change and compound interest.

Percentage change and reverse percentages

To express a change as a percentage, compare the change to the original amount, not the new one.

Percentage change =neworiginaloriginal×100= \dfrac{\text{new} - \text{original}}{\text{original}} \times 100. A profit of GBP 15 on a GBP 60 cost is 1560×100=25%\tfrac{15}{60} \times 100 = 25\% profit.

Simple and compound interest

Interest is a percentage paid on a balance over time.

Simple interest adds the same fixed amount each year, calculated on the original sum only: 200200 at 5%5\% simple interest earns 200×0.05=10200 \times 0.05 = 10 each year, so GBP 30 over three years.

Compound interest pays interest on the new balance each year, so the growth compounds. Multiply by the same factor each period, which means raising the multiplier to a power.

So GBP 1000 at 4%4\% for 33 years grows to 1000×1.043=1124.861000 \times 1.04^3 = 1124.86. Repeated percentage change (population growth, depreciation) uses exactly the same power method.

Everyday financial contexts

The Welsh specification frames percentages in genuinely useful settings, so expect questions on pay, bills and value for money. A payslip question might ask for the income tax due once a tax-free allowance is removed, or the take-home pay after deductions. A "best buy" question gives two pack sizes and asks which is better value: divide price by quantity to get a unit cost (price per gram or per millilitre) and compare. VAT adds a fixed percentage to a net price, so a GBP 200 item plus 20%20\% VAT costs 200×1.2=240200 \times 1.2 = 240, and removing VAT from a gross price is a reverse percentage, dividing by 1.21.2.

Depreciation and repeated change

Depreciation is compound decrease: a car worth GBP 12000 losing 15%15\% of its value each year is worth 12000×0.85n12000 \times 0.85^n after nn years, so 12000×0.853=7369.5012000 \times 0.85^3 = 7369.50 after three years. The same structure models a population falling by a fixed percentage or a savings account growing. The single most marked decision in all of this is whether a change is a one-off (single multiplier), simple (add the same amount each period) or compound (raise the multiplier to a power), so read each question carefully for the word "each year".

Why this matters

Financial percentages are among the most heavily examined and most real-world parts of WJEC Mathematics, matching the specification's emphasis on personal finance and everyday numeracy. The multiplier method unifies increase, decrease, reverse percentages and compound change into one reliable approach, and recognising when growth is simple (add each time) versus compound (multiply each time) is the single most marked distinction in this topic.

Exam-style practice questions

Practice questions written in the style of WJEC exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

WJEC 20193 marksA coat costing GBP 80 is reduced by 15 percent in a sale. Work out the sale price. (Unit 2, calculator.)
Show worked answer →

A 15%15\% reduction leaves 85%85\% of the price, so use the multiplier 0.850.85.

80×0.85=6880 \times 0.85 = 68.

The sale price is GBP 68. Markers award a mark for the multiplier 0.850.85 (or for finding 15%15\% of 80=1280 = 12), a mark for the method, and a mark for the answer GBP 68. Finding 15%15\% and forgetting to subtract it from 8080 is the usual slip.

WJEC 20214 marksGBP 2000 is invested at 3 percent compound interest per year. Find the value after 4 years, to the nearest penny. (Unit 2, calculator.)
Show worked answer →

Compound interest multiplies by 1.031.03 each year, so over 44 years multiply by 1.0341.03^4.

2000×1.034=2000×1.12550881=2251.017622000 \times 1.03^4 = 2000 \times 1.12550881 = 2251.01762.

To the nearest penny the value is GBP 2251.02. Markers give a mark for the multiplier 1.031.03, a mark for raising it to the power 44, a mark for the calculation, and a mark for correct rounding. Using simple interest (4×3%=12%4 \times 3\% = 12\%, giving GBP 2240) is the classic error.

Related dot points

Sources & how we know this