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WalesCombined ScienceSyllabus dot point

What is total internal reflection, and how is it used in optical fibres?

Total internal reflection, the critical angle, and the use of total internal reflection in optical fibres and prisms.

A focused answer to the WJEC GCSE Science Double Award Unit 3 topic on total internal reflection, covering the critical angle, the conditions for total internal reflection, and its use in optical fibres and prisms.

Generated by Claude Opus 4.88 min answer

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  1. What this dot point is asking
  2. What total internal reflection is
  3. The critical angle
  4. Using total internal reflection
  5. Why optical fibres are useful
  6. The critical angle and density
  7. Total internal reflection versus a mirror
  8. Try this

What this dot point is asking

WJEC Double Award Unit 3 wants you to explain total internal reflection and the critical angle, and describe its use in optical fibres and prisms.

What total internal reflection is

Normally, when light reaches a boundary, some refracts out and some reflects. But as the angle of incidence increases, more light reflects, until at the critical angle all of it reflects.

The critical angle

For glass, the critical angle is about 42 degrees.

Using total internal reflection

  • Optical fibres: a thin glass fibre carries light (or infrared) by total internal reflection. The light hits the sides at more than the critical angle, so it keeps reflecting along the fibre, even around bends, carrying telephone and internet data quickly and with little loss.
  • Prisms: right-angled glass prisms reflect light through 90 or 180 degrees by total internal reflection. They are used in periscopes and binoculars, giving sharper reflections than a mirror.

Why optical fibres are useful

Optical fibres can carry huge amounts of information as pulses of light, much more than electrical wires, and the signal loses little energy along the way. The light is kept inside the fibre by total internal reflection, so it can travel long distances and around corners. This is why optical fibres are used for high-speed internet and telephone networks, and in medical endoscopes to see inside the body. Linking the use back to total internal reflection is the key to these application questions.

The critical angle and density

The size of the critical angle depends on how much the two materials differ in optical density. A material in which light slows down a lot (a very dense material such as diamond) has a small critical angle, so total internal reflection happens easily, even at quite shallow angles. This is why cut diamonds sparkle: light entering them is totally internally reflected many times before coming back out. A material that bends light less has a larger critical angle. Knowing that a denser material has a smaller critical angle helps explain why some materials are better than others for optical fibres and prisms.

Total internal reflection versus a mirror

Prisms that use total internal reflection are often better than mirrors for reflecting light. A normal mirror reflects from a silvered surface behind the glass, which absorbs a little light and can give faint extra reflections, so the image is slightly dimmer and less sharp. With total internal reflection, all the light is reflected and there is no silvering to absorb it, giving a brighter, sharper reflection. This is why good binoculars and periscopes use prisms rather than mirrors, which is a common reason asked for in exams.

Try this

Q1. What happens to light at an angle greater than the critical angle? [1 mark]

  • Cue. It is totally internally reflected (all reflected back inside).

Q2. Name one use of total internal reflection. [1 mark]

  • Cue. Optical fibres (or prisms in periscopes and binoculars).

Exam-style practice questions

Practice questions written in the style of WJEC exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

WJEC style4 marksExplain the conditions needed for total internal reflection to occur.
Show worked answer →

A Unit 3 explain question worth 4 marks. Reward: the light must be travelling in the more dense material towards a less dense one (for example glass to air) (1); the angle of incidence must be greater than the critical angle (1); when this happens, none of the light passes out (refracts) and it is all reflected back inside (1); the reflection still obeys the law of reflection (1). Markers credit travelling from dense to less dense, the angle exceeding the critical angle, and all the light reflecting. A common error is to omit the critical angle condition.

WJEC style3 marksDescribe how total internal reflection is used to send signals along an optical fibre.
Show worked answer →

A Unit 3 application question. Reward: light (or infrared) enters the fibre and hits the sides at an angle greater than the critical angle (1); so it is totally internally reflected along the fibre, bouncing from side to side (1); this lets the signal travel along the fibre, even around bends, with little loss, carrying data quickly (1). Markers credit the angle exceeding the critical angle, repeated total internal reflection, and the signal travelling along the fibre. A common error is to say the light refracts out.

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