Skip to main content
ScotlandApplications of MathematicsSyllabus dot point

How do you keep units consistent and report a result with the right accuracy and tolerance?

Working with units and dimensional consistency, converting between units, rounding appropriately, and using tolerance, absolute error and percentage error to judge whether a result is acceptable.

A focused answer to the SQA Higher Applications of Mathematics content on units and accuracy, covering unit conversion and consistency, rounding to a stated accuracy, and absolute, percentage and tolerance error in a real context.

Generated by Claude Opus 4.89 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

Have a quick question? Jump to the Q&A page

Jump to a section
  1. What this dot point is asking
  2. Units and dimensional consistency
  3. Rounding to a sensible accuracy
  4. Absolute and percentage error
  5. Tolerance
  6. Why this matters in modelling
  7. Try this

What this dot point is asking

The SQA wants you to keep units consistent through a calculation, convert between units correctly, round a result to a sensible accuracy, and judge whether a value is acceptable using tolerance and error. These skills underpin every modelling and finance question, because an answer with the wrong units or unrealistic precision loses marks.

Units and dimensional consistency

A model only makes sense if every quantity is in compatible units. Before substituting into a formula, convert everything to one system, for example all lengths to metres or all times to hours. If a speed is in kilometres per hour and a time is in minutes, you must convert the time to hours first.

A common chain of conversions: 11 metre =100= 100 cm =1000= 1000 mm; 11 km =1000= 1000 m; 11 hour =60= 60 minutes =3600= 3600 seconds; 11 litre =1000= 1000 ml. To convert a rate, convert the numerator and denominator separately.

Rounding to a sensible accuracy

Report a result to an accuracy that matches the data and the context. Money is rounded to the nearest penny, a length measured to the nearest millimetre should not be quoted to thousandths of a millimetre, and a population is a whole number. Carry full precision through the working and round only at the end, because rounding early introduces error that grows through a calculation.

A figure given to 33 significant figures, such as 1410014\,100, claims accuracy to the nearest hundred; quoting 14053.2714\,053.27 from rounded input data overstates how precise the model really is.

Absolute and percentage error

When a measured or modelled value differs from a true or target value, two measures describe the gap.

The percentage error always divides by the true value, not the measured value. A small absolute error can still be a large percentage error if the true value is small: an error of 22 mm on a 1010 mm part is 20%20\%, but the same 22 mm on a 22 m beam is only 0.1%0.1\%. Percentage error lets you compare the seriousness of errors on quantities of different sizes.

Tolerance

In manufacturing and engineering a measurement is acceptable if it lies within a stated tolerance of the target. A specification of 50±0.450 \pm 0.4 mm means any value from 49.649.6 mm to 50.450.4 mm is acceptable.

The lower limit is target minus tolerance and the upper limit is target plus tolerance. A value passes if lower limit \le value \le upper limit. Tolerance is how a real process allows for unavoidable variation while keeping parts usable.

Why this matters in modelling

A model fed inconsistent units gives nonsense, and a result quoted too precisely misleads a reader into trusting it more than the data allows. Stating units, rounding sensibly, and reporting error or tolerance is part of communicating a model honestly, which the SQA rewards directly.

Try this

Q1. Convert 2.52.5 litres to millilitres, and a speed of 7272 km/h to metres per second. [2 marks]

  • Cue. 2.5×1000=25002.5 \times 1000 = 2500 ml; 72×1000÷3600=2072 \times 1000 \div 3600 = 20 m/s.

Q2. A component is specified as 25±0.625 \pm 0.6 mm. State the acceptable range and decide whether 24.324.3 mm passes. [3 marks]

  • Cue. Range 24.424.4 mm to 25.625.6 mm; 24.324.3 mm is below 24.424.4 mm, so it fails.

Q3. A model predicts 340340 but the true value is 325325. Find the percentage error. [2 marks]

  • Cue. Absolute error =15= 15; percentage error =15325×100=4.6%= \dfrac{15}{325} \times 100 = 4.6\%.

Exam-style practice questions

Practice questions written in the style of SQA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

SQA Higher Apps style4 marksA machine part is specified as 5050 mm with a tolerance of ±0.4\pm 0.4 mm. State the acceptable range, and decide whether parts measuring 49.549.5 mm and 50.350.3 mm pass.
Show worked answer →

The tolerance gives a range from 500.4=49.650 - 0.4 = 49.6 mm to 50+0.4=50.450 + 0.4 = 50.4 mm (2 marks).

The part at 49.549.5 mm is below 49.649.6 mm, so it is outside tolerance and is rejected (1 mark).

The part at 50.350.3 mm lies between 49.649.6 mm and 50.450.4 mm, so it is within tolerance and passes (1 mark). Markers reward the correct lower and upper limits and a clear accept or reject decision for each part.

SQA Higher Apps style4 marksA surveyor measures a distance as 128128 m but the true distance is 130130 m. Find the absolute error and the percentage error, and state whether the measurement meets a tolerance of 2%2\%.
Show worked answer →

The absolute error is the size of the difference, 128130=2|128 - 130| = 2 m (1 mark).

The percentage error is absolute errortrue value×100=2130×100=1.54%\dfrac{\text{absolute error}}{\text{true value}} \times 100 = \dfrac{2}{130} \times 100 = 1.54\% (2 marks).

Since 1.54%1.54\% is less than the allowed 2%2\%, the measurement is within tolerance and is acceptable (1 mark). Markers reward dividing by the true value, not the measured value, and comparing against the stated tolerance.

Related dot points

Sources & how we know this