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How do torque, moment of inertia and angular momentum govern rotation?

Torque and moment of inertia, the rotational form of Newton's second law, rotational kinetic energy, angular momentum and its conservation.

An SQA Advanced Higher Physics answer on rotational dynamics, covering torque, moment of inertia, the rotational form of Newton's second law, rotational kinetic energy, angular momentum and the conservation of angular momentum.

Generated by Claude Opus 4.815 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this key area is asking
  2. Torque and moment of inertia
  3. The rotational form of Newton's second law
  4. Rotational kinetic energy
  5. Angular momentum and its conservation
  6. Examples in context
  7. Try this

What this key area is asking

The SQA wants you to use torque as the rotational equivalent of force, the moment of inertia as the rotational equivalent of mass, the relationship τ=Iα\tau = I\alpha as the rotational form of Newton's second law, rotational kinetic energy, and angular momentum with its conservation when no external torque acts.

Torque and moment of inertia

For a single point mass at radius rr, I=mr2I = mr^2; for several discrete masses, I=mr2I = \sum mr^2. Extended bodies have standard results given on the data sheet (for example a uniform rod, a solid disc, a solid sphere). The same mass has a larger moment of inertia when its material is further from the axis, which is why a hollow ring is harder to spin up than a solid disc of equal mass.

The rotational form of Newton's second law

A resultant torque produces an angular acceleration inversely proportional to the moment of inertia. Doubling the torque doubles α\alpha; doubling II halves it. Every rotational problem about getting something spinning starts from this relationship, just as linear problems start from F=maF = ma.

Rotational kinetic energy

For a rolling object, total kinetic energy is 12mv2+12Iω2\tfrac{1}{2}mv^2 + \tfrac{1}{2}I\omega^2, and because v=rωv = r\omega the two share the available energy. This is why a hoop rolls down a slope more slowly than a solid cylinder of the same mass: the hoop's larger II takes a bigger share of the energy as rotation, leaving less for translation.

Angular momentum and its conservation

Conservation of angular momentum is the rotational analogue of conservation of linear momentum. If II changes while no external torque acts, ω\omega must change to keep IωI\omega constant: I1ω1=I2ω2I_1\omega_1 = I_2\omega_2. This single idea explains a spinning skater, a diver tucking to flip faster, and a collapsing star spinning up.

Examples in context

A figure skater pulls in their arms to reduce II and spin faster, conserving angular momentum. A flywheel stores large rotational kinetic energy because of its high moment of inertia, smoothing out an engine's power delivery. A neutron star spins hundreds of times per second because the collapse of its progenitor dramatically reduced II. A gyroscope resists changes to its axis because of its large angular momentum, which is why it is used for stabilisation and navigation.

Try this

Q1. State the rotational equivalent of mass in dynamics. [1 mark]

  • Cue. The moment of inertia, II.

Q2. A torque of 6.0 N m6.0\ \text{N m} acts on a body of moment of inertia 3.0 kg m23.0\ \text{kg m}^2. Find the angular acceleration. [2 marks]

  • Cue. α=τI=6.03.0=2.0 rad s2\alpha = \frac{\tau}{I} = \frac{6.0}{3.0} = 2.0\ \text{rad s}^{-2}.

Q3. State what happens to the angular velocity of an isolated spinning body when its moment of inertia is reduced. [1 mark]

  • Cue. It increases, because angular momentum IωI\omega is conserved.

Exam-style practice questions

Practice questions written in the style of SQA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

SQA AH style5 marksA solid disc of moment of inertia 0.45extkgm20.45 ext{kg m}^2 is acted on by a torque of 1.8extNm1.8 ext{N m}. Calculate the angular acceleration and the angular velocity reached after 4.04.0 s from rest.
Show worked answer →

Use the rotational form of Newton's second law, τ=Iα\tau = I\alpha.

Angular acceleration: α=τI=1.80.45=4.0 rad s2\alpha = \frac{\tau}{I} = \frac{1.8}{0.45} = 4.0\ \text{rad s}^{-2}.

Angular velocity from ω=ω0+αt\omega = \omega_0 + \alpha t with ω0=0\omega_0 = 0: ω=0+4.0×4.0=16 rad s1\omega = 0 + 4.0 \times 4.0 = 16\ \text{rad s}^{-1}.

Markers reward rearranging τ=Iα\tau = I\alpha, the angular-acceleration value, and then applying the angular equation of motion for the final angular velocity, both with units.

SQA AH style4 marksA skater spinning at 2.0extrads12.0 ext{rad s}^{-1} with moment of inertia 4.0extkgm24.0 ext{kg m}^2 pulls in their arms, reducing their moment of inertia to 1.6extkgm21.6 ext{kg m}^2. Calculate their new angular velocity and explain the principle used.
Show worked answer →

With no external torque, angular momentum L=IωL = I\omega is conserved.

Conservation: I1ω1=I2ω2I_1\omega_1 = I_2\omega_2.

Substitute: 4.0×2.0=1.6×ω24.0 \times 2.0 = 1.6 \times \omega_2, so ω2=8.01.6=5.0 rad s1\omega_2 = \frac{8.0}{1.6} = 5.0\ \text{rad s}^{-1}.

The skater spins faster because reducing the moment of inertia must be balanced by a larger angular velocity to keep IωI\omega constant.

Markers reward stating conservation of angular momentum, the correct rearrangement and value, and the physical explanation.

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