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How do inductors oppose changing current and store energy in a magnetic field?

Self-inductance and back emf, Lenz's law, the energy stored in an inductor, the growth and decay of current in an RL circuit, and inductive reactance.

An SQA Advanced Higher Physics answer on inductors, covering self-inductance and back emf, Lenz's law, the energy stored in an inductor's magnetic field, the growth and decay of current in an RL circuit, and inductive reactance in a.c. circuits.

Generated by Claude Opus 4.814 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this key area is asking
  2. Self-inductance and back emf
  3. Lenz's law
  4. Energy stored in an inductor
  5. RL circuits and inductive reactance
  6. Examples in context
  7. Try this

What this key area is asking

The SQA wants you to understand self-inductance and the back emf an inductor produces, apply Lenz's law, use the energy stored in an inductor E=12LI2E = \tfrac{1}{2}LI^2, describe the growth and decay of current in an RL circuit, and understand inductive reactance in a.c. circuits.

Self-inductance and back emf

When the current through a coil changes, the magnetic flux it produces changes, and by Faraday's law this induces an emf. This back emf opposes the change in current, so an inductor resists being switched on or off quickly. The faster the current changes, the larger the back emf, which is why breaking an inductive circuit can produce a large voltage spike.

Lenz's law

If the current is increasing, the back emf opposes it (trying to keep the current down); if decreasing, the back emf acts to maintain it. Lenz's law guarantees energy conservation: the induced effect can never reinforce its own cause, or you would get energy from nothing. It is the principle behind electromagnetic braking and the reason inductors smooth current changes.

Energy stored in an inductor

Building up the current does work against the back emf, and that work is stored in the magnetic field. When the circuit is broken, the current falls rapidly, the field collapses, and the stored energy is released, frequently as a spark across the opening switch. This mirrors the capacitor's 12CV2\tfrac{1}{2}CV^2, with current and inductance replacing voltage and capacitance.

RL circuits and inductive reactance

The gradual growth and decay are the inductive analogue of the capacitor's exponential charging, set by the ratio L/RL/R. In a.c., because the inductor opposes change most strongly when the current changes fastest, it impedes high frequencies more than low ones. An inductor therefore passes low frequencies (and d.c.) readily while opposing high frequencies, exactly opposite to a capacitor, which is why the two are paired in filters.

Examples in context

Spark suppression circuits protect switches that control inductive loads such as motors and relays, because breaking the current produces a large back emf. Transformers rely on the changing flux of one coil inducing an emf in another, the mutual version of self-inductance. Inductors in power supplies smooth current ripple, opposing rapid changes. Induction hobs and electromagnetic braking use Lenz's law, where induced currents oppose the motion that creates them.

Try this

Q1. Write the relationship for the back emf of an inductor in terms of LL and the rate of change of current. [1 mark]

  • Cue. ε=LdIdt\varepsilon = -L\frac{dI}{dt}.

Q2. Write the relationship for the energy stored in an inductor carrying current II. [1 mark]

  • Cue. E=12LI2E = \tfrac{1}{2}LI^2.

Q3. State how an inductor's opposition to a.c. changes as the frequency increases. [1 mark]

  • Cue. It increases (the inductive reactance rises with frequency).

Exam-style practice questions

Practice questions written in the style of SQA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

SQA AH style4 marksAn inductor of 0.50 H0.50\ \text{H} carries a current that changes at a rate of 30 A s130\ \text{A s}^{-1}. Calculate the magnitude of the back emf induced.
Show worked answer →

The back emf is ε=LdIdt\varepsilon = -L\dfrac{dI}{dt}, so its magnitude is LdIdtL\dfrac{dI}{dt}.

Substitute: ε=0.50×30=15 V\varepsilon = 0.50 \times 30 = 15\ \text{V}.

The minus sign (Lenz's law) shows the emf opposes the change in current; the question asks only for the magnitude.

Markers reward the relationship, the value with unit, and recognising that the back emf opposes the change in current.

SQA AH style4 marksAn inductor of 0.20 H0.20\ \text{H} carries a steady current of 3.0 A3.0\ \text{A}. Calculate the energy stored in its magnetic field, and explain where this energy goes when the circuit is broken.
Show worked answer →

The energy stored in an inductor is E=12LI2E = \tfrac{1}{2}LI^2.

Substitute: E=12×0.20×3.02=12×0.20×9.0=0.90 JE = \tfrac{1}{2} \times 0.20 \times 3.0^2 = \tfrac{1}{2} \times 0.20 \times 9.0 = 0.90\ \text{J}.

When the circuit is broken the current tries to fall rapidly, inducing a large back emf; the stored energy is released, often as a spark across the switch.

Markers reward the energy relationship, the value with unit, and that the energy is released (commonly as a spark) when the current is interrupted.

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