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What are the circle theorems and how do you use them to find angles and write proofs?

Know and use the circle theorems (angle at the centre, angle in a semicircle, angles in the same segment, cyclic quadrilateral, tangent properties and alternate segment) to find angles and construct reasoned proofs (Higher tier).

A focused answer to the OCR GCSE Mathematics Higher geometry content on circle theorems, covering the angle at the centre, angle in a semicircle, angles in the same segment, cyclic quadrilaterals, tangents and the alternate segment theorem.

Generated by Claude Opus 4.812 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this dot point is asking
  2. Angles at the centre and circumference
  3. Same segment and cyclic quadrilaterals
  4. Tangents and the alternate segment
  5. Why circle theorems matter

What this dot point is asking

OCR reference G10 at Higher tier covers the circle theorems: the relationships between angles, chords, tangents and radii in a circle, used both to find angles and to write reasoned proofs. Circle theorems are a signature Higher-tier topic that tests AO2 reasoning heavily, because every step needs a named justification. They build directly on the basic angle facts and are a reliable source of multi-mark questions.

Angles at the centre and circumference

The most-used theorem relates a central angle to an inscribed one.

So if a central angle is 80∘80^\circ, the inscribed angle on the same arc is 40∘40^\circ. The semicircle case is a frequent shortcut: any triangle with the diameter as one side has a right angle opposite it. Identifying which arc both angles stand on is the decisive step.

Same segment and cyclic quadrilaterals

Two theorems concern angles inside the circle.

So two inscribed angles standing on the same chord are equal, no matter where on the arc their vertices sit. In a cyclic quadrilateral ABCDABCD, angle AA + angle CC = 180∘180^\circ and angle BB + angle DD = 180∘180^\circ. These let you chain through a diagram, finding one angle and using it to find the next.

Tangents and the alternate segment

Tangents introduce right angles and a subtle equal-angle rule.

The tangent-radius right angle often combines with Pythagoras to find a length. The equal-tangents fact creates isosceles triangles, which then give equal base angles. The alternate segment theorem is the hardest to spot, so look for a tangent, a chord from the point of contact, and an inscribed angle in the far segment.

Why circle theorems matter

Circle theorems are the clearest test of geometric reasoning at GCSE, and OCR awards marks specifically for the named justification at each step, in line with the 3030 percent AO2 weighting. They reward a systematic approach: label what you know, find an angle you can justify, then use it to unlock the next. Quoting the theorem precisely ("angle at the centre is twice the angle at the circumference") is as important as the arithmetic.

Exam-style practice questions

Practice questions written in the style of OCR exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

OCR 20193 marksAA, BB and CC are points on a circle with centre OO. The angle AOCAOC at the centre is 130∘130^\circ. Work out the angle ABCABC at the circumference, giving a reason. (Higher, Paper 4, calculator.)
Show worked answer β†’

The angle at the centre is twice the angle at the circumference when both stand on the same arc.

So angle ABC=1302=65∘ABC = \dfrac{130}{2} = 65^\circ.

The reason is "the angle at the centre is twice the angle at the circumference".

Markers award a mark for halving, a mark for 65∘65^\circ, and a mark for the reason. OCR requires the named theorem as part of the AO2 communication; an answer without the reason loses a mark.

OCR 20214 marksABCDABCD is a cyclic quadrilateral. Angle DAB=95∘DAB = 95^\circ and angle ABC=70∘ABC = 70^\circ. Work out angles BCDBCD and ADCADC, giving reasons. (Higher, Paper 4, calculator.)
Show worked answer β†’

Opposite angles of a cyclic quadrilateral sum to 180∘180^\circ.

Angle BCD=180βˆ’95=85∘BCD = 180 - 95 = 85^\circ (opposite to DABDAB).

Angle ADC=180βˆ’70=110∘ADC = 180 - 70 = 110^\circ (opposite to ABCABC).

Markers give a mark for each angle and a mark for the reason "opposite angles of a cyclic quadrilateral sum to 180∘180^\circ". Pairing the wrong opposite angles is the standard error, so identify which angles face each other across the quadrilateral.

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