How do we measure the rate of a reaction and read rates from a graph?
Methods for following the rate of a reaction, calculating mean rate from quantity and time, drawing and interpreting rate graphs, and finding the rate at a given moment using a tangent.
A focused answer to OCR Gateway GCSE Chemistry A topic C5.1 on measuring and calculating rates, covering the methods for following a reaction, calculating mean rate from quantity and time, interpreting rate graphs, and finding the rate at a given moment using a tangent.
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What this dot point is asking
OCR wants you to describe methods for following the rate of a reaction, calculate the mean rate from a quantity and a time, draw and interpret rate graphs, and (Higher) find the rate at a given moment by drawing a tangent. This is the quantitative, practical side of rates.
Methods for following a reaction
The method chosen depends on the reaction: a gas-producing reaction suits a gas syringe or balance, while a reaction that forms a precipitate suits the disappearing-cross method.
Calculating mean rate
Interpreting rate graphs
When you plot the quantity of product against time, the shape of the curve tells you about the rate:
- The line is steepest at the start, because the reactant concentration is highest, so collisions are most frequent and the rate is fastest.
- The line gradually flattens as reactants are used up and the concentration falls, so the rate decreases.
- The line becomes flat (horizontal) when the reaction has finished (a reactant has run out), so the rate is zero.
A reaction with a faster rate gives a steeper initial line that levels off sooner, at the same final amount (if the same amount of reactant is used).
Finding the rate at a given moment (Higher)
Exam-style practice questions
Practice questions written in the style of OCR exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.
OCR 20194 marksIn a reaction that produces a gas, of gas is collected in the first 30 seconds. Calculate the mean rate of reaction over this time in per second, and describe two methods that could be used to follow the rate of a reaction that produces a gas.Show worked answer →
A C5.1 calculation and method question. Reward: the mean rate is the quantity of product divided by the time: . Two methods to follow a gas-producing reaction: (1) collect the gas in a gas syringe and measure the volume of gas at regular time intervals, or (2) stand the reaction flask on a balance and measure the loss in mass at regular intervals as the gas escapes. Markers credit the correct mean rate of 1.6 cm3 per second, and two valid methods (gas syringe for volume, or balance for mass loss). A third valid method is timing how long a fixed amount of product takes to form. A common slip is to divide time by volume instead of volume by time.
OCR 20214 marksA student plots a graph of the volume of gas produced against time for a reaction. Explain why the gradient (slope) of the graph is steepest at the start and becomes zero at the end, and describe how to find the rate at a particular time from the graph.Show worked answer →
A Higher tier graph-interpretation question. Reward: the gradient is steepest at the start because the concentration of the reactants is highest then, so collisions are most frequent and the reaction is fastest. As the reaction proceeds, the reactants are used up, so their concentration falls, collisions become less frequent, and the rate (gradient) decreases. The gradient becomes zero when the line is flat (horizontal) because the reaction has finished (a reactant has run out), so no more gas is produced. To find the rate at a particular time, draw a tangent to the curve at that point and calculate its gradient (change in volume divided by change in time). Markers credit the highest concentration giving the steepest initial gradient, the falling concentration reducing the rate, the flat line meaning the reaction has stopped, and drawing a tangent to find the rate at a point. A common error is to read a single coordinate rather than a gradient.
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