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How do you find the area and perimeter of 2D shapes and the surface area and volume of 3D solids?

Calculate the area and perimeter of rectangles, triangles, parallelograms, trapezia, circles and sectors; and the surface area and volume of prisms, cylinders, pyramids, cones and spheres.

A focused answer to the Eduqas GCSE Mathematics geometry content on area and volume, covering the area and perimeter of 2D shapes including circles and sectors, and the surface area and volume of prisms, cylinders, pyramids, cones and spheres.

Generated by Claude Opus 4.812 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this dot point is asking
  2. Area and perimeter of 2D shapes
  3. Circles and sectors
  4. Volume of 3D solids
  5. Surface area
  6. Units and why measurement matters

What this dot point is asking

The Eduqas geometry content asks you to find the area and perimeter of standard 2D shapes (rectangles, triangles, parallelograms, trapezia, circles and sectors), and the surface area and volume of 3D solids (prisms, cylinders, pyramids, cones and spheres). Measurement is one of the most heavily tested areas, mixing formula recall with multi-step problem solving. Some formulae are given on the Eduqas list (the sphere and cone), while others must be recalled (rectangle, triangle, circle), so knowing which is which, and when to use each, is essential. It runs across both tiers and both components.

Area and perimeter of 2D shapes

Each common shape has an area formula, and the perimeter is the total distance around the edge.

So a trapezium with parallel sides 66 cm and 1010 cm and perpendicular height 44 cm has area 12(6+10)×4=32\tfrac{1}{2}(6 + 10) \times 4 = 32 cm squared. A compound shape (an L-shape, say) is split into rectangles whose areas are added. The perpendicular height is the recurring trap: in a triangle or parallelogram you must use the height at right angles to the base, not a sloping edge.

Circles and sectors

The circle formulae are core knowledge and must be recalled.

The most common slip is confusing area (πr2\pi r^2) with circumference (2πr2\pi r), or using the diameter where the formula needs the radius. A sector is simply the fraction θ360\dfrac{\theta}{360} of the whole circle, so a quarter circle (9090^\circ) has a quarter of the area and a quarter of the circumference as its arc.

Volume of 3D solids

Volume measures the space inside a solid, and a prism's volume follows one general rule.

For the curved solids, the cylinder is πr2h\pi r^2 h, the sphere is 43πr3\tfrac{4}{3}\pi r^3 and the cone is 13πr2h\tfrac{1}{3}\pi r^2 h; the sphere and cone formulae are given on the Eduqas list, so use them directly.

Surface area

Surface area is the total area of all the faces of a solid, so a systematic count of every face prevents omissions. A cuboid has six rectangular faces in three matching pairs. A cylinder has two circular ends (2πr22\pi r^2) plus a curved surface that unrolls into a rectangle of area 2πrh2\pi r h. A cone has a circular base (πr2\pi r^2) plus a curved surface πrl\pi r l, where ll is the slant height (found by Pythagoras from rr and the vertical height). Listing the faces before adding is the reliable method, and Eduqas often leaves answers in terms of π\pi on the non-calculator paper.

Units and why measurement matters

Keeping units straight is half the battle in measurement questions. Length is measured in single units (cm), area in square units (cm squared) because it is length times length, and volume in cubic units (cm cubed) because it is length times length times length. This also governs conversions: 11 m =100= 100 cm, so 11 m squared =1002=10000= 100^2 = 10000 cm squared and 11 m cubed =1003=1000000= 100^3 = 1000000 cm cubed, a point Eduqas tests directly. Measurement underpins a great deal of real mathematics, from packaging and construction to the capacity of containers, and it connects to the compound-measures work where volume feeds into density. Because these questions reward a clear method, always write the formula, substitute with units, and state the unit of the answer.

Exam-style practice questions

Practice questions written in the style of WJEC Eduqas exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Eduqas 20183 marksA circle has radius 7 cm. Work out its area, giving your answer to 1 decimal place. (Foundation, Component 2, calculator.)
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The area of a circle is A=πr2A = \pi r^2.

Substitute r=7r = 7: A=π×72=49πA = \pi \times 7^2 = 49\pi.

Evaluate: 49×3.14159=153.949 \times 3.14159\ldots = 153.9 cm squared to 1 decimal place.

Markers award a mark for the correct formula, a mark for 49π49\pi, and a mark for the evaluated answer. Using the circumference formula 2πr2\pi r, or using the diameter instead of the radius, are the common errors.

Eduqas 20224 marksA solid cylinder has radius 5 cm and height 12 cm. Work out its total surface area, giving your answer in terms of π\pi. (Higher, Component 1, non-calculator.)
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The total surface area is two circular ends plus the curved surface.

Two ends: 2×πr2=2×π×52=50π2 \times \pi r^2 = 2 \times \pi \times 5^2 = 50\pi.

Curved surface: 2πrh=2×π×5×12=120π2\pi r h = 2 \times \pi \times 5 \times 12 = 120\pi.

Total: 50π+120π=170π50\pi + 120\pi = 170\pi cm squared.

Markers give marks for the area of the ends, the curved surface area, and the total in terms of π\pi. Forgetting the curved surface, or counting only one end, are the usual omissions.

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