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How do you calculate wave speed from frequency and wavelength?

The wave speed equation: wave speed as frequency times wavelength, the distance-over-time form, and rearranging to find frequency or wavelength.

A focused answer to Edexcel GCSE Physics 4.6, covering the two forms of the wave speed equation, wave speed as frequency times wavelength and as distance over time, rearranging to find frequency or wavelength, and using consistent units, with worked calculations.

Generated by Claude Opus 4.89 min answer

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  1. What this dot point is asking
  2. The frequency-wavelength form
  3. The distance-time form
  4. Units and a key fact
  5. How Edexcel examines this
  6. Try this

What this dot point is asking

Edexcel statement 4.6 wants you to recall and use both forms of the wave speed equation: wave speed as frequency times wavelength, and wave speed as distance over time. You must be able to rearrange the equation to find any of the quantities.

The frequency-wavelength form

This is the form you reach for when a question gives frequency and wavelength. It says that the speed of a wave is how many waves pass per second multiplied by the length of each wave. Because it has three quantities, it rearranges two ways: f=vλf = \dfrac{v}{\lambda} to find frequency and λ=vf\lambda = \dfrac{v}{f} to find wavelength.

The distance-time form

This second form is the ordinary speed equation applied to a wave, and is useful when you are told how far a wave travels in a given time (for example a sound echo or a ripple crossing a tank). Both forms give the same wave speed, so you can combine them: if you find the speed from v=xtv = \dfrac{x}{t}, you can then use v=fλv = f\lambda to find a frequency or wavelength.

Units and a key fact

For electromagnetic waves, the constant speed in a vacuum links frequency and wavelength inversely: as one goes up, the other goes down. This is why gamma rays (high frequency) have very short wavelengths while radio waves (low frequency) have long wavelengths, a point that returns in the electromagnetic spectrum.

How Edexcel examines this

The wave speed equation is one of the most frequently examined calculations in the whole specification and appears on both tiers, both as a standalone problem and embedded in questions on the electromagnetic spectrum, sound and the core practical. The mark scheme usually awards a mark for the correct equation, so write v=fλv = f\lambda (or v=xtv = \frac{x}{t}) before substituting, then a mark for substitution and a mark for the answer with its unit. Questions are set in all three rearrangements, so practise finding speed, frequency and wavelength. A favourite is to combine the two forms: measure a wave's speed from a distance and time, then use v=fλv = f\lambda to find its wavelength or frequency. Unit conversions catch many candidates, so convert wavelengths to metres and check that frequencies are in hertz. For electromagnetic waves, examiners may give the speed of light and ask for a wavelength or frequency, testing standard form; here the inverse relationship between frequency and wavelength at fixed speed is the key idea.

Try this

Q1. A wave has a frequency of 50Hz50\,\text{Hz} and a wavelength of 2m2\,\text{m}. Calculate its speed. [2 marks]

  • Cue. v=fλ=50×2=100m/sv = f\lambda = 50 \times 2 = 100\,\text{m/s}.

Q2. A wave travels at 12m/s12\,\text{m/s} with a wavelength of 3m3\,\text{m}. Calculate its frequency. [2 marks]

  • Cue. f=vλ=123=4Hzf = \dfrac{v}{\lambda} = \dfrac{12}{3} = 4\,\text{Hz}.

Exam-style practice questions

Practice questions written in the style of Pearson Edexcel exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Edexcel 20193 marksA sound wave has a frequency of 440Hz440\,\text{Hz} and a wavelength of 0.75m0.75\,\text{m}. Calculate the speed of the sound wave.
Show worked answer →

Use the wave speed equation v=f×λv = f \times \lambda with f=440Hzf = 440\,\text{Hz} and λ=0.75m\lambda = 0.75\,\text{m} (1 mark). Substitute: v=440×0.75=330m/sv = 440 \times 0.75 = 330\,\text{m/s} (2 marks for substitution and answer with the unit). Markers reward selecting v=fλv = f\lambda, correct substitution and the unit m/s\text{m/s}. Multiplying or dividing the wrong way, or a unit slip, loses marks; note the answer matches the typical speed of sound in air.

Edexcel 20213 marksA water wave travels at 1.5m/s1.5\,\text{m/s} with a frequency of 3Hz3\,\text{Hz}. Calculate the wavelength of the wave.
Show worked answer →

Rearrange v=f×λv = f \times \lambda to λ=vf\lambda = \dfrac{v}{f} (1 mark for the rearrangement). Substitute v=1.5m/sv = 1.5\,\text{m/s} and f=3Hzf = 3\,\text{Hz}: λ=1.53=0.5m\lambda = \dfrac{1.5}{3} = 0.5\,\text{m} (2 marks). Markers reward making the wavelength the subject and the correct division. Dividing frequency by speed (inverting the fraction) is the common error.

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