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What stock forms and sizes does timber come in, and how is the required quantity calculated?

Typical stock forms, types and sizes of natural and manufactured timbers used to calculate and determine the required quantity, including regular sections, mouldings, dowels and sheets, with cross-sectional area and board-size calculations.

A focused answer to Edexcel GCSE Design and Technology Timbers category 7.5 on the stock forms and sizes of timber, covering regular sections, mouldings, dowels and sheets, and calculating cross-sectional area, board sizes and the required quantity.

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  1. What this dot point is asking
  2. Stock forms and types
  3. Sizes and how timber is specified
  4. Calculating cross-sectional area and quantity

What this dot point is asking

This is Edexcel 7.5, on the typical stock forms, types and sizes of timber used to calculate and determine the required quantity. Edexcel names the stock forms and types (7.5.1) and the sizes (7.5.2). Because Section B guarantees 5 marks of calculations, the cross-sectional area, board size and quantity sums here are high-value. This page pairs with the scales of production and quantity-production techniques.

Stock forms and types

Buying timber in standard stock forms is cheaper and quicker than having it specially cut. The designer chooses the nearest stock size above the part needed, then cuts it down, which also helps plan how to minimise waste.

Sizes and how timber is specified

Note that a nominal sawn size (for example "50 by 50") is larger than the finished PAR size, because planing removes a few millimetres from each face. Sizes are quoted in both imperial and metric in industry.

Calculating cross-sectional area and quantity

The cross-sectional area of a rectangular section is:

A=width×heightA = \text{width} \times \text{height}

For a round dowel of diameter dd, the cross-sectional area is:

A=πr2=π(d2)2A = \pi r^2 = \pi \left(\frac{d}{2}\right)^2

To find how many parts come from a stock length or sheet, divide the stock dimension by the part dimension and round down to a whole number, allowing for the saw cut (kerf) lost at each cut:

number of parts=stock lengthpart length+saw cut (rounded down)\text{number of parts} = \frac{\text{stock length}}{\text{part length} + \text{saw cut}}\ \text{(rounded down)}

Efficient cutting (nesting parts and minimising offcuts) reduces waste and cost, which links to sustainability and to the quantity-production techniques.

Exam-style practice questions

Practice questions written in the style of Pearson Edexcel exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Edexcel 20224 marksA shelf is cut from a board 2440 mm long. Each shelf is 600 mm long with a 5 mm saw cut (kerf) lost between cuts. Calculate the maximum number of shelves from one board and the length of timber wasted. (4 marks)
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A calculation question (Section B carries 5 marks of calculations). Markers award method and the correct values with units.

Each shelf plus one saw cut uses 600+5=605 mm600 + 5 = 605\ \text{mm}. Number of shelves: 2440605=4.03\dfrac{2440}{605} = 4.03, so a maximum of 4 shelves (you must round down because you cannot cut a part shelf) (2 marks).

Timber used: 4×600=2400 mm4 \times 600 = 2400\ \text{mm} of shelf, plus saw cuts. The waste is the board length minus the shelf length used: 24402400=40 mm2440 - 2400 = 40\ \text{mm} (allowing for the saw cuts within this), so about 40 mm is wasted (2 marks).

Markers reward rounding down to a whole number of shelves and the waste calculation. A common error is rounding 4.03 up to 5, or forgetting the saw cut (kerf).

Edexcel 20213 marksA timber post has a square cross-section of 45 mm by 45 mm. Calculate its cross-sectional area in square millimetres. (3 marks)
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A 3-mark calculation. Markers award the method and the value with units.

Cross-sectional area of a rectangle (or square) is width times height: A=45×45=2025 mm2A = 45 \times 45 = 2025\ \text{mm}^2 (2 marks for method and value).

The unit is square millimetres (mm2\text{mm}^2) because two lengths are multiplied (1 mark for the correct unit).

Markers reward width times height and the squared unit. A frequent error is giving the answer in mm instead of mm squared, or adding the sides instead of multiplying.

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