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Why do the Group 7 halogens get less reactive down the group, and what are displacement reactions?

Group 7 the halogens: their physical properties and trends, their reactions to form ions and compounds, the decreasing reactivity down the group, and halogen displacement reactions.

A focused answer to Edexcel GCSE Chemistry topic 6, covering the physical properties and trends of the Group 7 halogens, how they form 1- ions and covalent molecules, the decreasing reactivity down the group explained by electronic structure, and halogen displacement reactions with their ionic equations.

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  1. What this dot point is asking
  2. Physical properties and trends
  3. Forming ions and compounds
  4. The reactivity trend and its explanation
  5. Displacement reactions
  6. Try this

What this dot point is asking

Edexcel wants you to describe the physical properties and trends of the Group 7 halogens, explain how they form 1βˆ’1- ions and covalent molecules, describe and explain the decreasing reactivity down the group in terms of electronic structure, and write equations for halogen displacement reactions. The trend explanation and displacement equations are reliable marks.

The halogens are reactive non-metals that exist as diatomic molecules (F2F_2, Cl2Cl_2, Br2Br_2, I2I_2). Going down the group:

  • They get darker in colour (chlorine pale green, bromine orange-brown, iodine grey-black).
  • Their melting and boiling points increase, so at room temperature chlorine is a gas, bromine a liquid and iodine a solid.

All halogen atoms have seven electrons in their outer shell.

Forming ions and compounds

Halogens are one electron short of a full outer shell, so they are very reactive:

  • With metals they gain one electron to form a 1βˆ’1- ion (a halide), forming ionic compounds such as sodium chloride.
  • With non-metals they share electrons to form covalent molecules such as hydrogen chloride, HClHCl.

Because they all have seven outer electrons, the halogens have similar chemical properties and react in similar ways.

The reactivity trend and its explanation

Reactivity decreases down the group, the opposite of Group 1. The explanation is about how easily the atom gains an electron:

Displacement reactions

Because reactivity decreases down the group, chlorine displaces bromine and iodine, and bromine displaces iodine, but not the reverse. For example, chlorine added to potassium bromide solution turns it orange as bromine is released:

Cl2+2KBr→2KCl+Br2Cl_2 + 2KBr \rightarrow 2KCl + Br_2

The ionic equation Cl2+2Brβˆ’β†’2Clβˆ’+Br2Cl_2 + 2Br^- \rightarrow 2Cl^- + Br_2 shows chlorine gaining electrons (reduced) and bromide ions losing them (oxidised), so it is a redox reaction.

Try this

Q1. State the number of electrons in the outer shell of a Group 7 atom. [1 mark]

  • Cue. Seven.

Q2. State the trend in melting point down Group 7. [1 mark]

  • Cue. The melting point increases down the group.

Q3. Write the ionic equation for chlorine displacing iodine from sodium iodide solution. [2 marks]

  • Cue. Cl2+2Iβˆ’β†’2Clβˆ’+I2Cl_2 + 2I^- \rightarrow 2Cl^- + I_2.

Exam-style practice questions

Practice questions written in the style of Pearson Edexcel exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Edexcel 20184 marksChlorine is bubbled through potassium bromide solution. State what you would observe, write the ionic equation, and explain why this reaction happens.
Show worked answer β†’

A 4-mark halogen displacement question.

The colourless solution turns orange (or brown) as bromine is formed (1 mark for the observation). The ionic equation is Cl2+2Brβˆ’β†’2Clβˆ’+Br2Cl_2 + 2Br^- \rightarrow 2Cl^- + Br_2 (1 mark). The reaction happens because chlorine is more reactive than bromine (1 mark), so chlorine displaces bromine from the potassium bromide, taking its place as the more reactive halogen (1 mark).

Markers reward the colour change, the balanced ionic equation, and the more-reactive-halogen explanation.

Edexcel 20213 marksExplain why the reactivity of the Group 7 halogens decreases down the group, in terms of electronic structure.
Show worked answer β†’

A 3-mark trend-explanation question.

Halogens react by gaining one electron to complete their outer shell. Going down the group, the outer shell is further from the nucleus (1 mark) and is more shielded by inner shells, so the attraction for the incoming electron is weaker (1 mark). This means an electron is gained less easily down the group, so reactivity decreases (1 mark).

Markers reward "outer shell further from the nucleus", weaker attraction for the gained electron, and the conclusion that reactivity falls.

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