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How do we measure how fast galaxies recede, and how does this give the age of the Universe?

Redshift of distant galaxies and its cause, the redshift formula, Hubble's law relating distance and recession velocity, and estimating the age and size of the Universe.

A focused answer to Edexcel GCSE Astronomy statements 16.1 to 16.6, covering the redshift of distant galaxies and that it is caused by recession, the redshift formula, Hubble's law relating recession velocity to distance, and estimating the age and size of the Universe from the Hubble constant.

Generated by Claude Opus 4.811 min answer

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  1. What this dot point is asking
  2. Redshift and its cause
  3. The redshift formula
  4. Hubble's law
  5. The age and size of the Universe
  6. How Edexcel examines this
  7. Try this

What this dot point is asking

Edexcel statements 16.1 to 16.6 want you to know that galaxies beyond the Local Group show redshift, that redshift is caused by galaxies receding, to use the redshift formula λλ0λ0=vc\dfrac{\lambda - \lambda_0}{\lambda_0} = \dfrac{v}{c}, to use Hubble's law v=H0dv = H_0 d (including reading a gradient), and to estimate the age and size of the Universe from the Hubble constant.

Redshift and its cause

Redshift is the central observation of cosmology: nearly every distant galaxy is moving away, and the shift in its spectral lines measures how fast. The cause is recession (statement 16.2), ultimately because space itself is expanding and carrying the galaxies apart, so we are not at a special centre. Galaxies in the Local Group can show blueshift (Andromeda is approaching), but beyond it the expansion dominates and everything recedes.

The redshift formula

This is a key calculation. Find the change in wavelength (λλ0\lambda - \lambda_0), divide by the emitted wavelength λ0\lambda_0 to get the fractional redshift, then multiply by cc to get the velocity. The wavelength units cancel as long as they are the same top and bottom. The formula is on the data sheet, so the marks are for correct substitution and rearrangement.

Hubble's law

Hubble's law is the quantitative statement that the Universe is expanding uniformly: double the distance, double the recession speed. The proportionality is what you calculate with (v=H0dv = H_0 d, rearranged as needed) and what you read from a graph (the gradient gives H0H_0, statement 4c). Combined with a redshift-derived velocity, it gives the distance to a galaxy, extending the distance ladder to the farthest galaxies.

The age and size of the Universe

The estimate works by imagining the expansion reversed: if galaxies are flying apart at speeds proportional to their distances, they were all together a time 1/H0\approx 1/H_0 ago, which is the age of the Universe. This is statement 16.6. The value of H0H_0 therefore directly controls the estimated age, which is why measuring it precisely matters so much in cosmology.

How Edexcel examines this

This is telescopic Paper 2 content and a major calculation point. Two calculations recur: the redshift formula (find λλ0\lambda - \lambda_0, divide by λ0\lambda_0, multiply by cc for the velocity) and Hubble's law (v=H0dv = H_0 d, rearranged to find a distance or velocity), both from the data sheet. You may also read H0H_0 as the gradient of a velocity-distance graph. The redshift cause (recession) and Hubble's law (more distant galaxies recede faster) are tested by explanation, and the age of the Universe by the 1/H01/H_0 idea (running the expansion backwards), with a larger H0H_0 meaning a younger Universe. Synoptic links run to standard candles for the distances (Topic 13) and to the Big Bang evidence (next dot point). The commonest errors are reversing the redshift direction and mismatching units in Hubble's law, so keep redshift as increased wavelength and the units consistent.

Try this

Q1. State what the redshift of a distant galaxy tells us about its motion. [1 mark]

  • Cue. It is moving away from us (receding); a greater redshift means a faster recession.

Q2. State Hubble's law in its formula form. [1 mark]

  • Cue. v=H0dv = H_0 d (recession velocity equals the Hubble constant times distance).

Exam-style practice questions

Practice questions written in the style of Pearson Edexcel exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Edexcel 1AS0 20224 marksA galaxy emits a spectral line at a wavelength of 500nm500\,\text{nm}. It is observed at 510nm510\,\text{nm}. Using the redshift formula λλ0λ0=vc\dfrac{\lambda - \lambda_0}{\lambda_0} = \dfrac{v}{c} with c=3.0×108m/sc = 3.0 \times 10^8\,\text{m/s}, calculate the galaxy's radial velocity.
Show worked answer →

The change in wavelength is λλ0=510500=10nm\lambda - \lambda_0 = 510 - 500 = 10\,\text{nm} (1 mark). The redshift formula gives λλ0λ0=vc\dfrac{\lambda - \lambda_0}{\lambda_0} = \dfrac{v}{c}, so 10500=v3.0×108\dfrac{10}{500} = \dfrac{v}{3.0 \times 10^8} (1 mark). Rearranging, v=10500×3.0×108=0.02×3.0×108v = \dfrac{10}{500} \times 3.0 \times 10^8 = 0.02 \times 3.0 \times 10^8 (1 mark). So v=6.0×106m/sv = 6.0 \times 10^6\,\text{m/s} (1 mark). Markers reward finding the change in wavelength, substituting into the redshift formula, and the velocity of 6.0×106m/s6.0 \times 10^6\,\text{m/s}, with the galaxy receding because the wavelength has increased (redshift). Using the same wavelength units top and bottom cancels them.

Edexcel 1AS0 20214 marksA galaxy is moving away from us at 2000km/s2000\,\text{km/s}. Using Hubble's law v=H0dv = H_0 d with H0=68km/s/MpcH_0 = 68\,\text{km/s/Mpc}, calculate its distance in megaparsecs, and explain how the Hubble constant is used to estimate the age of the Universe.
Show worked answer →

Hubble's law is v=H0dv = H_0 d, so d=vH0d = \dfrac{v}{H_0} (1 mark). Substituting, d=20006829Mpcd = \dfrac{2000}{68} \approx 29\,\text{Mpc} (megaparsecs) (1 mark). The age of the Universe is estimated by assuming the expansion has been roughly constant and running it backwards: the age is approximately 1H0\dfrac{1}{H_0}, the time for galaxies moving apart at their current speeds to have reached their current separations (1 mark). So a larger Hubble constant implies a faster expansion and a younger Universe, and using 1/H01/H_0 (with consistent units) gives an age of order 14 billion years (1 mark). Markers reward rearranging Hubble's law to get about 29 Mpc, and explaining that the age is about 1/H01/H_0 (running the expansion backwards), so H0H_0 sets the estimated age.

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