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How do mechanisms change the type, direction or size of motion and force?

The four types of motion, mechanisms that change motion (levers, linkages, gears, pulleys, cams, cranks) and how they alter direction, speed and force.

A focused answer to AQA GCSE Engineering on the four types of motion and the mechanisms (levers, linkages, gears, pulleys, cams and cranks) that change the type, direction, speed or force of motion.

Generated by Claude Opus 4.89 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this dot point is asking
  2. The four types of motion
  3. Mechanisms that change motion
  4. Gear ratios
  5. Try this

What this dot point is asking

AQA wants you to name the four types of motion, recognise the common mechanisms, and explain how each changes the type, direction, speed or force of motion, including simple gear ratio calculations. Gear questions that ask for a ratio and an output speed are common, so be ready to calculate.

The four types of motion

Mechanisms that change motion

  • Levers: change the size and direction of a force about a pivot (fulcrum), giving mechanical advantage.
  • Linkages: join levers to change the direction or type of motion (a reverse-motion linkage flips direction).
  • Gears: meshing toothed wheels change rotary speed and torque; an idler gear between two gears changes the direction of rotation without changing the ratio.
  • Pulleys and belts: transfer rotary motion between shafts and change speed by the ratio of their diameters.
  • Cams and followers: change rotary motion into reciprocating (up-and-down) motion, the shape of the cam setting the movement.
  • Cranks and sliders: change rotary motion into reciprocating motion and back, as in a car engine.

Gear ratios

For a driver of 2020 teeth and a driven of 6060 teeth, the ratio is 60/20=360/20 = 3, so the output turns three times slower with about three times the torque. Gears always trade speed against turning force, which is the central idea examined. The same trade-off applies to a pulley-and-belt drive, where the ratio is set by the diameters of the two pulleys rather than teeth: a small driver pulley turning a large driven pulley gears down (slower, more torque), while a large driver turning a small driven gears up (faster, less torque). A compound gear train uses two or more pairs in series to reach a large overall ratio in a small space, the overall ratio being the product of the individual ratios.

Try this

Q1. Name the type of motion of a swinging pendulum. [1 mark]

  • Cue. Oscillating.

Q2. A driver gear of 1515 teeth drives a 4545-tooth gear. State the gear ratio. [1 mark]

  • Cue. 45/15=345/15 = 3, so 3:13:1.

Exam-style practice questions

Practice questions written in the style of AQA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

AQA 20184 marksA gear train has a driver gear with 2020 teeth meshing with a driven gear of 6060 teeth. Calculate the gear ratio and explain its effect on speed and torque.
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A good answer calculates the ratio and links it to speed and torque.

The gear ratio is driven teeth divided by driver teeth: 60/20=360 / 20 = 3, so a ratio of 3:13:1.

This means the driver turns three times for each turn of the driven gear, so the driven gear turns at one third of the speed. Because the gears trade speed for force, the torque (turning force) at the driven gear is increased about three times.

Markers reward the correct ratio calculation and the link that a higher ratio reduces output speed but increases torque.

AQA 20216 marksA driver gear of 1515 teeth turning at 300 rev/min300 \text{ rev/min} drives a gear of 4545 teeth. Calculate the gear ratio and the output speed, and explain how this gear train would be used in a hand-cranked winch.
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A good answer finds the ratio, applies it to the speed, and links the effect to the winch.

Gear ratio =driven teethdriver teeth=4515=3= \dfrac{\text{driven teeth}}{\text{driver teeth}} = \dfrac{45}{15} = 3, so 3:13:1.

Output speed =input speedgear ratio=3003=100 rev/min= \dfrac{\text{input speed}}{\text{gear ratio}} = \dfrac{300}{3} = 100 \text{ rev/min}.

In a winch, this gear-down trades speed for torque: the output turns three times slower than the input but with about three times the turning force, so a person can wind a heavy load by hand more easily, at the cost of turning the handle more times.

Markers reward the ratio of 3:13:1, the output speed of 100 rev/min100 \text{ rev/min}, and the explanation that gearing down increases torque to lift the load.

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