Skip to main content
EnglandBiologySyllabus dot point

What factors affect the rate of photosynthesis, and how are limiting factors used in greenhouses?

The limiting factors of photosynthesis (light intensity, carbon dioxide concentration, temperature and chlorophyll), the inverse square law for light, and the economics of controlling these factors in greenhouses.

A focused answer to AQA GCSE Biology 4.4.1.2, covering the limiting factors of photosynthesis, the inverse square law for light intensity, and how greenhouse growers control these factors economically.

Generated by Claude Opus 4.810 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

Have a quick question? Jump to the Q&A page

Jump to a section
  1. What this dot point is asking
  2. Limiting factors
  3. Interpreting rate graphs
  4. The inverse square law
  5. Photosynthesis in greenhouses
  6. Required practical
  7. Try this

What this dot point is asking

AQA wants you to explain the four limiting factors of photosynthesis, interpret rate graphs, use the inverse square law for light intensity (higher tier), and explain how greenhouse growers control these factors to increase yield economically. It links directly to the required practical on light intensity and photosynthesis.

Limiting factors

The four factors AQA wants are:

  • Light intensity: light supplies the energy for the reaction, so more light gives a faster rate, until another factor becomes limiting.
  • Carbon dioxide concentration: carbon dioxide is a raw material, so more of it increases the rate, again up to a limit. Air is only about 0.04 percent carbon dioxide, so it is often the limiting factor outdoors on a bright day.
  • Temperature: the reactions are controlled by enzymes, so the rate rises with temperature up to an optimum; too hot (above roughly 40 to 45 degrees Celsius) and the enzymes denature, so the rate falls sharply.
  • Chlorophyll: the amount of chlorophyll affects how much light can be absorbed. It can be reduced by disease (such as tobacco mosaic virus) or by a lack of magnesium ions, which the plant needs to make chlorophyll.

Interpreting rate graphs

On a rate-against-light-intensity graph the line rises steeply at first (light is limiting), then levels off (plateaus) when a different factor (carbon dioxide or temperature) becomes limiting. If you then repeat the experiment at a higher carbon dioxide concentration or higher temperature, the line plateaus at a higher rate, which proves that the second factor was the one limiting the first plateau. AQA often asks you to identify, from such a graph, which factor is limiting at a labelled point: where the line is still rising the named axis variable is limiting; where it is flat, something else is.

The inverse square law

For light intensity (higher tier), light obeys the inverse square law: intensity is proportional to 1d2\dfrac{1}{d^2}, where dd is the distance from the light source.

Photosynthesis in greenhouses

Commercial growers control the limiting factors to increase yield:

  • Adding artificial light so plants photosynthesise for longer and through the night.
  • Burning fuel such as paraffin to add carbon dioxide to the air and provide some heat at the same time.
  • Using heaters to raise the temperature towards the enzymes' optimum.

This all costs money, so the grower balances the extra cost against the increased yield and profit. The aim is to make every factor non-limiting so the plants photosynthesise as fast as possible.

Required practical

You can investigate the effect of light intensity on the rate of photosynthesis using pondweed such as Cabomba or Elodea. Count the bubbles of oxygen given off in a set time, or measure the volume of gas collected, at several distances from a lamp. Control temperature (the lamp heats the water, so use a heat shield or beaker of water as a filter) and carbon dioxide (add sodium hydrogencarbonate). Plot rate against light intensity (or against 1d2\dfrac{1}{d^2} at higher tier).

Try this

Q1. Explain why the rate of photosynthesis levels off as light intensity increases. [2 marks]

  • Cue. Light is no longer limiting; another factor (carbon dioxide or temperature) has become the limiting factor.

Q2. A lamp is moved from 10 cm10\ cm to 30 cm30\ cm from a plant. By what factor does the light intensity change? [2 marks]

  • Cue. Distance trebles, so intensity falls to 1/32=1/91/3^2 = 1/9 of the original.

Exam-style practice questions

Practice questions written in the style of AQA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

AQA 20204 marksA student investigated the effect of light intensity on the rate of photosynthesis using pondweed. They counted the number of oxygen bubbles released in one minute at different distances from a lamp. Describe a method the student could use and explain how they would make the investigation valid.
Show worked answer →

A 4-mark required-practical question rewards a clear method plus control of variables.

Method: place pondweed in a beaker of water with a lamp at a set distance, count the bubbles of gas released in one minute (or measure the gas volume), then repeat at several distances.

Validity: control the variables that are not being tested. Keep the temperature constant (use a water bath or heat shield so the lamp does not warm the water), keep the carbon dioxide concentration constant (for example add sodium hydrogencarbonate), and use the same piece of pondweed. Repeat each distance and take a mean to improve reliability.

Markers reward a workable method, naming light intensity as the independent variable and bubble count as the dependent variable, and at least two correctly controlled variables.

AQA 20223 marksA lamp is placed at a distance of 0.2 m from a plant. The lamp is then moved to a distance of 0.6 m. Calculate the factor by which the light intensity changes, using the inverse square law. Show your working.
Show worked answer →

A 3-mark higher-tier calculation rewards correct use of the inverse square law and clear working.

Light intensity is proportional to 1d2\dfrac{1}{d^2}. At 0.2 m0.2\ m the relative intensity is 10.22=10.04=25\dfrac{1}{0.2^2} = \dfrac{1}{0.04} = 25. At 0.6 m0.6\ m it is 10.62=10.36=2.78\dfrac{1}{0.6^2} = \dfrac{1}{0.36} = 2.78. The factor change is 2.7825=0.111\dfrac{2.78}{25} = 0.111, so the light intensity falls to about one ninth.

A faster route: the distance trebles, so intensity changes by 132=19\dfrac{1}{3^2} = \dfrac{1}{9}. Markers reward the inverse square relationship, correct substitution, and the answer one ninth (about 0.11).

Related dot points

Sources & how we know this