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How are characteristics inherited, and how do we predict the outcomes of genetic crosses?

The key genetic terms (gene, allele, genotype, phenotype, dominant, recessive, homozygous, heterozygous), monohybrid inheritance and genetic crosses, codominance and sex linkage, and the use of genetic diagrams to predict offspring ratios.

A CCEA Life and Health Sciences answer on inheritance: the key genetic terms, monohybrid crosses and genetic diagrams, codominance and sex linkage, and predicting offspring ratios with Punnett squares.

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  1. What this dot point is asking
  2. Key genetic terms
  3. Monohybrid crosses and Punnett squares
  4. Codominance and sex linkage
  5. Examples in context
  6. Try this

What this dot point is asking

CCEA wants you to use the key genetic terms correctly, explain monohybrid inheritance and complete genetic crosses, explain codominance and sex linkage, and use genetic diagrams (Punnett squares) to predict the genotype and phenotype ratios of offspring. It builds directly on the molecular genetics of the previous dot point, applying the gene concept to how characteristics pass from parents to offspring.

Key genetic terms

These terms are the language of inheritance, so using them precisely is essential. Alleles are written as letters: a capital letter for the dominant allele and the same letter in lower case for the recessive (for example R and r). A homozygous dominant individual is RR, a heterozygous individual is Rr (which shows the dominant phenotype because R masks r), and a homozygous recessive individual is rr (which shows the recessive phenotype). Because every individual carries two alleles of each gene (one from each parent) and passes one to each offspring through the gametes, inheritance can be predicted.

Monohybrid crosses and Punnett squares

The Punnett square is a grid with one parent's gametes across the top and the other's down the side; filling each cell combines the gametes to give the offspring genotypes. From the genotypes you read off the phenotypes using the dominance rule. A 3 to 1 phenotype ratio is the hallmark of a heterozygous cross for a simple dominant and recessive gene. A test cross (crossing an organism showing the dominant phenotype with a homozygous recessive) reveals whether the unknown parent is homozygous (all offspring dominant) or heterozygous (a 1 to 1 ratio of phenotypes).

Codominance and sex linkage

In codominance, neither allele is fully dominant, so both alleles are expressed in the heterozygote, giving a third phenotype. The human ABO blood groups are a classic example: the alleles for A and B are codominant (a person with both shows blood group AB), while the allele for O is recessive. In sex linkage, the gene is carried on a sex chromosome, usually the X chromosome. Because females are XX and males are XY, a male has only one copy of an X-linked gene; so a recessive X-linked condition such as haemophilia or red-green colour blindness is expressed in a male with a single recessive allele, while a female would need two. This is why such conditions are more common in males, and why a carrier mother can pass the condition to her sons.

Examples in context

Example 1. ABO blood groups and transfusions. The codominant A and B alleles and the recessive O allele determine a person's blood group, which must be matched for safe transfusion. Predicting a child's possible blood groups from the parents' genotypes is a direct medical application of codominant inheritance, linking genetics to the health-science focus of the qualification.

Example 2. Genetic counselling for sex-linked disease. A family with a history of haemophilia may seek genetic counselling. Using sex-linkage reasoning and a genetic diagram, a counsellor can estimate the chance that a carrier mother's sons will be affected and her daughters will be carriers, showing how inheritance prediction informs real health decisions.

Try this

Q1. Define the terms genotype and phenotype. [2 marks]

  • Cue. Genotype is the alleles an organism has; phenotype is the observable characteristic.

Q2. Two heterozygous parents (Bb) are crossed. State the expected phenotype ratio of the offspring. [2 marks]

  • Cue. 3 dominant to 1 recessive (from a 1 BB to 2 Bb to 1 bb genotype ratio).

Q3. Explain why red-green colour blindness is more common in males than females. [2 marks]

  • Cue. The gene is on the X chromosome; males have only one X, so one recessive allele is enough, while females need two.

Exam-style practice questions

Practice questions written in the style of CCEA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

CCEA A2 56 marksIn humans, the allele for the ability to roll the tongue (R) is dominant to the allele for being unable to roll the tongue (r). Two heterozygous tongue-rollers have children. Use a genetic diagram to predict the ratio of tongue-rollers to non-rollers in their offspring.
Show worked answer →

A full-mark answer states the parental genotypes and gametes, completes a Punnett square and gives the ratio.

Parental genotypes: both parents are heterozygous tongue-rollers, so each is Rr.

Gametes: each parent produces gametes carrying R or r.

Punnett square (R and r from one parent across the top, R and r from the other down the side) gives offspring: RR, Rr, Rr, rr.

Genotype ratio: 1 RR to 2 Rr to 1 rr.

Phenotype ratio: RR, Rr and Rr can all roll the tongue (R is dominant), and only rr cannot. So the ratio of tongue-rollers to non-rollers is 3 to 1.

Markers reward correct parental genotypes Rr, the gametes, a correct Punnett square, and the 3 to 1 phenotype ratio with reasoning.

CCEA A2 55 marksHaemophilia is caused by a recessive allele carried on the X chromosome. A carrier mother (not affected) and an unaffected father have children. Explain why haemophilia is more common in their sons than their daughters.
Show worked answer →

The answer must use sex linkage and the genotypes of sons and daughters.

Sex linkage: the allele is on the X chromosome. Females are XX and males are XY, so a male has only one X chromosome and only one copy of the gene.

Genotypes: the carrier mother is X(H)X(h) (one normal allele H, one haemophilia allele h) and the unaffected father is X(H)Y. Daughters receive an X from each parent; to be affected a daughter would need two h alleles, but she always gets the father's normal X(H), so she cannot be affected (she may be a carrier). Sons receive the Y from the father and an X from the mother; if a son receives the mother's X(h) he is affected, because he has no second X to mask it.

Conclusion: because a son needs only one copy of the recessive allele (he has a single X) while a daughter would need two, haemophilia is more common in sons.

Markers reward the X chromosome location, males having a single X, the carrier mother passing X(h) to sons, and the conclusion that one copy affects a son but a daughter needs two.

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