What controls the rate of a reaction, and how do catalysts and temperature change it?
Collision theory and activation energy, the effects of concentration, pressure, surface area, temperature and catalysts on rate, the Maxwell-Boltzmann distribution, and how a catalyst provides an alternative pathway of lower activation energy.
A CCEA A-Level Chemistry answer on reaction kinetics, covering collision theory and activation energy, the effects of concentration, pressure, surface area, temperature and catalysts on rate, the Maxwell-Boltzmann distribution, and how catalysts lower the activation energy by providing an alternative route.
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What this dot point is asking
CCEA wants you to use collision theory to explain reaction rate, define activation energy, explain the effects of concentration, pressure, surface area, temperature and catalysts, sketch and interpret the Maxwell-Boltzmann distribution, and explain how a catalyst increases rate by lowering activation energy.
Collision theory and activation energy
The rate depends on the frequency of these successful collisions.
Factors affecting rate
- Concentration and pressure: more particles per unit volume, so more frequent collisions and a higher rate.
- Surface area: breaking a solid into smaller pieces exposes more particles, raising collision frequency.
- Temperature: particles move faster (more frequent collisions) and a greater proportion exceed , which is the dominant effect.
For concentration, pressure and surface area, only the collision frequency changes; the proportion of collisions that succeed stays the same because the energy distribution of the molecules is unchanged. Temperature is different and far more powerful, because it changes both the collision frequency and, much more importantly, the proportion of molecules with energy at or above . This is why a rough rule of thumb is that a rise in temperature roughly doubles the rate, whereas doubling the concentration only doubles the collision frequency. Measuring a rate experimentally usually means following a quantity that changes with time, such as the volume of gas produced, the mass lost, or the time taken for a fixed amount of product (the clock reaction), then comparing initial gradients.
The Maxwell-Boltzmann distribution
Catalysts
On a Maxwell-Boltzmann diagram, the catalyst moves to a lower value, so a larger proportion of molecules now have enough energy to react. The catalyst does not change the enthalpy change. Catalysts may be homogeneous (in the same phase as the reactants, like the chlorine radicals that catalyse ozone breakdown) or heterogeneous (in a different phase, like the solid iron in the Haber process, on whose surface the reaction takes place). In both cases the principle is the same: a new route with a lower activation energy.
Examples in context
Example 1. Catalytic converters in cars. A catalytic converter uses a heterogeneous catalyst (platinum, palladium and rhodium spread over a honeycomb to maximise surface area) to speed up reactions that turn toxic carbon monoxide and nitrogen oxides into carbon dioxide and nitrogen. The catalyst lowers the activation energy of these reactions so they proceed fast enough in the few seconds the gases spend in the exhaust. The large surface area is a deliberate design choice, the same principle as powdering a solid reactant.
Example 2. Enzymes as biological catalysts. Enzymes lower the activation energy of reactions in living cells, allowing them to proceed quickly at body temperature (about ) instead of needing high heat. Catalase, for example, speeds the breakdown of hydrogen peroxide into water and oxygen by an enormous factor. This is a clear demonstration that a catalyst lets a reaction reach a workable rate at a low temperature, exactly the trade-off CCEA expects candidates to articulate.
Try this
Q1. State the two conditions for a successful collision. [2 marks]
- Cue. Energy at or above , and the correct orientation.
Q2. Explain how a catalyst increases the rate of reaction. [2 marks]
- Cue. It provides an alternative pathway with a lower , so a greater proportion of molecules can react.
Exam-style practice questions
Practice questions written in the style of CCEA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.
CCEA 20206 marksSketch a Maxwell-Boltzmann distribution for a gas and mark the activation energy Ea. On the same axes, draw a second curve for the same gas at a higher temperature. Use the diagram to explain why a small rise in temperature can produce a large increase in reaction rate.Show worked answer →
Markers want a correctly shaped curve, a correctly labelled second curve, and an explanation tied to the area beyond .
The curve must start at the origin (no molecules with zero energy), rise to a peak (the most probable energy), then fall and approach the energy axis without ever touching it. The activation energy is marked well to the right of the peak, and the shaded area to the right of represents the molecules able to react.
The higher-temperature curve is drawn with its peak lower and shifted to the right, and the total area under it stays the same (the number of molecules is unchanged). Crucially, the area to the right of is much larger.
The explanation: raising the temperature shifts the distribution so that a far greater proportion of molecules now have energy at or above . Because this fraction rises steeply, even a modest temperature rise (often a rise roughly doubles the rate) gives a large increase in the number of successful collisions per second, and so a large increase in rate.
Markers penalise a curve that crosses or touches the axis, a second curve with a different area, or an explanation that only mentions faster movement without the fraction exceeding .
CCEA 20183 marksState and explain the effect of increasing the surface area of a solid reactant on the rate of its reaction with a solution.Show worked answer →
A short collision-theory explanation.
Increasing the surface area (for example by grinding a lump into a powder) increases the rate of reaction.
The explanation is that more of the solid's particles are now exposed at the surface and available to collide with the particles in the solution. This increases the frequency of collisions per second, so the frequency of successful collisions also increases, and the rate goes up.
Markers reward the statement that rate increases, the idea of more exposed particles or surface, and the link to more frequent collisions. Simply saying there are more collisions without explaining why loses a mark.
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Sources & how we know this
- CCEA GCE Chemistry specification — CCEA (2016)