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Why is benzene so stable, and how does it react?

The structure and delocalised bonding of benzene, the evidence for delocalisation, electrophilic substitution reactions including nitration and halogenation, and a comparison of the reactivity of benzene with alkenes and of phenol with benzene.

A CCEA A-Level Chemistry answer on aromatic chemistry, covering the delocalised structure of benzene, the thermochemical and bond-length evidence for delocalisation, electrophilic substitution by nitration and halogenation, and the relative reactivity of benzene, alkenes and phenol.

Generated by Claude Opus 4.812 min answer

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  1. What this dot point is asking
  2. The structure of benzene
  3. Electrophilic substitution
  4. Reactivity comparisons
  5. Examples in context
  6. Try this

What this dot point is asking

CCEA wants you to describe the delocalised bonding in benzene, quote the evidence for it, write the mechanism and conditions for electrophilic substitution (nitration and halogenation), and compare the reactivity of benzene with alkenes and of phenol with benzene.

The structure of benzene

Electrophilic substitution

Benzene reacts by electrophilic substitution, keeping the delocalised ring intact.

Nitration: concentrated HNO3\text{HNO}_3 and concentrated H2SO4\text{H}_2\text{SO}_4 at about 50 degrees C50\ \text{degrees C}. The electrophile is NO2+\text{NO}_2^+:

HNO3+2H2SO4NO2++2HSO4+H3O+\text{HNO}_3 + 2\text{H}_2\text{SO}_4 \rightarrow \text{NO}_2^+ + 2\text{HSO}_4^- + \text{H}_3\text{O}^+

C6H6+NO2+C6H5NO2+H+\text{C}_6\text{H}_6 + \text{NO}_2^+ \rightarrow \text{C}_6\text{H}_5\text{NO}_2 + \text{H}^+

Halogenation: Cl2\text{Cl}_2 or Br2\text{Br}_2 with a halogen carrier (AlCl3\text{AlCl}_3, FeBr3\text{FeBr}_3) that polarises the halogen to give the electrophile Br+\text{Br}^+.

Reactivity comparisons

Examples in context

The industrial nitration of benzene to nitrobenzene is the first step toward aniline (phenylamine) dyes and toward TNT, and uses exactly the concentrated HNO3/H2SO4\text{HNO}_3/\text{H}_2\text{SO}_4 mixture above with careful temperature control to avoid dinitration. The phenol-versus-benzene contrast appears in CCEA practical work: phenol decolourises bromine water and forms a white precipitate of 2,4,6-tribromophenol instantly, whereas benzene does not react, demonstrating how the oxygen lone pair activates the ring.

Try this

Q1. State the type of hybridisation of each carbon atom in benzene. [1 mark]

  • Cue. sp2\text{sp}^2.

Q2. Give the electrophile responsible for the nitration of benzene and the equation for its formation. [2 marks]

  • Cue. NO2+\text{NO}_2^+; HNO3+2H2SO4NO2++2HSO4+H3O+\text{HNO}_3 + 2\text{H}_2\text{SO}_4 \rightarrow \text{NO}_2^+ + 2\text{HSO}_4^- + \text{H}_3\text{O}^+.

Q3. Explain why phenol is more reactive toward electrophiles than benzene. [2 marks]

  • Cue. An oxygen lone pair is delocalised into the ring, increasing electron density and attracting electrophiles more strongly.

Exam-style practice questions

Practice questions written in the style of CCEA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

CCEA 20194 marksDescribe the bonding in benzene and outline two pieces of evidence that support the delocalised model rather than the Kekule model.
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Each carbon in benzene is sp2\text{sp}^2 hybridised and forms three sigma bonds (to two carbons and one hydrogen). The remaining p orbital on each carbon overlaps sideways with its neighbours to form a ring of delocalised pi electrons above and below the plane.

Evidence 1, bond lengths: all six carbon-carbon bonds are identical at 0.139 nm0.139\ \text{nm}, between a single bond (0.154 nm0.154\ \text{nm}) and a double bond (0.134 nm0.134\ \text{nm}). The Kekule model predicts alternating long and short bonds, which is not observed.

Evidence 2, enthalpy of hydrogenation: the measured value for benzene (208 kJ mol1-208\ \text{kJ mol}^{-1}) is less exothermic than three times that of cyclohexene (3×120=360 kJ mol13 \times -120 = -360\ \text{kJ mol}^{-1}). Benzene is about 152 kJ mol1152\ \text{kJ mol}^{-1} more stable than the Kekule structure predicts, the delocalisation (resonance) energy.

Markers reward (1) the delocalised pi system from p-orbital overlap, (2) equal bond lengths, (3) the enthalpy-of-hydrogenation comparison, (4) the conclusion of extra stability.

CCEA 20213 marksState the reagents and conditions for the nitration of benzene and explain why benzene undergoes substitution rather than addition.
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Reagents: concentrated nitric acid and concentrated sulfuric acid (the catalyst). Conditions: warm at about 50 degrees C50\ \text{degrees C}, keeping the temperature below 55 degrees C55\ \text{degrees C} to avoid multiple substitution.

The electrophile is NO2+\text{NO}_2^+, generated by HNO3+2H2SO4NO2++2HSO4+H3O+\text{HNO}_3 + 2\text{H}_2\text{SO}_4 \rightarrow \text{NO}_2^+ + 2\text{HSO}_4^- + \text{H}_3\text{O}^+.

Benzene undergoes substitution rather than addition because substitution restores the stable delocalised ring of pi electrons, whereas addition would permanently destroy the delocalisation and lose the associated stability. Markers reward (1) both concentrated acids and the temperature, (2) the NO2+\text{NO}_2^+ electrophile, (3) preservation of the stable delocalised system as the reason for substitution.

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