OCR A-Level Physics A Electrons, waves and photons overview quiz quiz

$v = nAIe$

$v = \frac{nAe}{I}$

$v = \frac{Ie}{nA}$

$v = \frac{I}{nAe}$

$1.2\ \text{V}$

$0.30\ \text{V}$

$0.90\ \text{V}$

$1.5\ \text{V}$

$4.5\ \Omega$

$2.0\ \Omega$

$9.0\ \Omega$

$18\ \Omega$

Frequency and wavelength are directly proportional at a fixed wave speed, so both rise together

The wave speed depends only on the amplitude of the wave, not on its frequency or wavelength

At fixed wave speed, frequency and wavelength are inversely proportional

Wavelength increases whenever the frequency increases, provided the wave speed is held fixed

A quarter of a wavelength

One wavelength

Two wavelengths

Half a wavelength

$d\sin\theta = n\lambda$

$d\cos\theta = n\lambda$

$d\sin\theta = (n + \tfrac{1}{2})\lambda$

$\lambda\sin\theta = nd$

The light is fully transmitted out of the denser medium without any of it being reflected

The light is totally internally reflected

The light travels straight along the normal as it leaves the boundary into the less dense medium

The frequency of the light changes as it crosses from the denser medium into the less dense one

Gamma, X-ray, ultraviolet, visible, infrared, microwave, radio

Visible, infrared, microwave, radio, ultraviolet, X-ray, gamma

Radio, microwave, infrared, visible, ultraviolet, X-ray, gamma

Radio, infrared, microwave, visible, X-ray, ultraviolet, gamma

Brighter light gives a larger photocurrent once the frequency is above the threshold value

Light is able to travel through a vacuum, where there is no medium for it to pass through

Light reflects from a polished mirror, obeying the usual law of reflection at the surface

There is a threshold frequency below which no electrons are emitted

$4.0 \times 10^{-19}\ \text{J}$

$9.1 \times 10^{-48}\ \text{J}$

$1.1 \times 10^{-48}\ \text{J}$

$4.0 \times 10^{19}\ \text{J}$

They are exactly equal, because the two particles are travelling at the very same speed

The electron has the longer wavelength

The proton has the longer wavelength, because its far greater mass gives it more momentum

Neither particle has a de Broglie wavelength, since only photons have a wavelength at all