Skip to main content
EnglandFurther MathsSyllabus dot point

How do polar coordinates describe points and curves, and how do you convert between polar and Cartesian form?

Polar coordinates, conversion between polar and Cartesian form, and sketching polar curves r = f(theta) including circles, lines, cardioids and spirals.

A focused answer to the OCR A-Level Further Mathematics A content on polar coordinates and curves, covering the polar representation of a point, conversion between polar and Cartesian coordinates, and sketching polar curves r = f(theta) such as circles, lines, cardioids and spirals, including finding where the curve meets the pole and its symmetry.

Generated by Claude Opus 4.811 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

Have a quick question? Jump to the Q&A page

Jump to a section
  1. What this dot point is asking
  2. Polar coordinates of a point
  3. Converting between polar and Cartesian
  4. Converting a polar equation
  5. Sketching polar curves
  6. Try this

What this dot point is asking

OCR wants you to represent a point in polar coordinates (r,θ)(r, \theta), convert between polar and Cartesian coordinates using x=rcosθx = r\cos\theta and y=rsinθy = r\sin\theta, and sketch polar curves r=f(θ)r = f(\theta), identifying key features such as where the curve passes through the pole, its maximum rr, and its symmetry, for standard curves including circles, lines, cardioids and spirals.

Polar coordinates of a point

In polar coordinates a point is located by how far it is from the pole and in what direction, rather than by horizontal and vertical displacement. The angle θ\theta is measured anticlockwise from the initial line.

Converting between polar and Cartesian

The conversion formulae come straight from right-angled triangle trigonometry, with the point at distance rr and angle θ\theta.

Converting a polar equation

To turn a polar equation into Cartesian form, look to create the combinations r2r^2, rcosθr\cos\theta and rsinθr\sin\theta, which become x2+y2x^2 + y^2, xx and yy. Multiplying both sides by rr is the standard trick when the equation has a lone rr or a cosθ\cos\theta to be paired with one.

Sketching polar curves

To sketch r=f(θ)r = f(\theta), build a small table of rr at θ=0,π4,π2,\theta = 0, \tfrac{\pi}{4}, \tfrac{\pi}{2}, \ldots, note where r=0r = 0 (the curve passes through the pole, often giving a tangent direction) and where rr reaches its maximum, and use any symmetry (a curve in cosθ\cos\theta is symmetric about the initial line, while one in sinθ\sin\theta is symmetric about the line θ=π2\theta = \tfrac{\pi}{2}). Recognise the standard shapes: r=ar = a (circle radius aa), θ=α\theta = \alpha (half-line), r=a(1+cosθ)r = a(1 + \cos\theta) (cardioid, a heart shape), r=acosθr = a\cos\theta (a circle through the pole), and r=aθr = a\theta (an Archimedean spiral that widens steadily as θ\theta increases). Plotting just a handful of well-chosen points, together with the zeros and maxima of rr, is usually enough to produce an accurate sketch.

Polar coordinates set up the area formula for polar curves and connect to the modulus-argument form of complex numbers, where rr and θ\theta play the same roles.

Try this

Q1. Convert r=3r = 3 to Cartesian form. [1 mark]

  • Cue. r2=9r^2 = 9 gives x2+y2=9x^2 + y^2 = 9, a circle of radius 33.

Q2. Find where the cardioid r=2(1cosθ)r = 2(1 - \cos\theta) passes through the pole. [2 marks]

  • Cue. r=0r = 0 when cosθ=1\cos\theta = 1, that is θ=0\theta = 0.

Exam-style practice questions

Practice questions written in the style of OCR exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

OCR 20194 marksConvert the polar equation r=4cosθr = 4\cos\theta to Cartesian form, and describe the curve.
Show worked answer →

Multiply both sides by rr (M1): r2=4rcosθr^2 = 4r\cos\theta.

Use r2=x2+y2r^2 = x^2 + y^2 and rcosθ=xr\cos\theta = x (M1, A1): x2+y2=4xx^2 + y^2 = 4x.

Complete the square (A1): x24x+y2=0x^2 - 4x + y^2 = 0, so (x2)2+y2=4(x - 2)^2 + y^2 = 4.

This is a circle of radius 22 centred at (2,0)(2, 0) (passing through the pole).

Markers reward multiplying by rr, the standard substitutions, completing the square, and identifying the circle.

OCR 20225 marksA curve has polar equation r=1+cosθr = 1 + \cos\theta for 0θ<2π0 \le \theta < 2\pi. Find the values of θ\theta where the curve passes through the pole, and state the maximum value of rr and where it occurs.
Show worked answer →

The curve passes through the pole where r=0r = 0 (M1): 1+cosθ=01 + \cos\theta = 0, so cosθ=1\cos\theta = -1, giving θ=π\theta = \pi (A1).

The maximum of rr occurs when cosθ\cos\theta is greatest, that is cosθ=1\cos\theta = 1 at θ=0\theta = 0 (M1): then r=1+1=2r = 1 + 1 = 2 (A1).

So rmax=2r_{\max} = 2 at θ=0\theta = 0, and the curve reaches the pole at θ=π\theta = \pi; this is a cardioid (A1).

Markers reward setting r=0r = 0, the value θ=π\theta = \pi, the maximum r=2r = 2 at θ=0\theta = 0, and recognising the cardioid shape.

Related dot points

Sources & how we know this