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How do matrices represent geometric transformations of the plane and of space, and how do you compose and reverse them?

Matrices as linear transformations in two and three dimensions (rotations, reflections, enlargements, stretches and shears), composition by multiplication, invariant points and lines, and the determinant as an area or volume scale factor.

A focused answer to the OCR A-Level Further Mathematics A content on matrices as linear transformations, covering the standard matrices for rotations, reflections, enlargements, stretches and shears in two and three dimensions, composing transformations by matrix multiplication, finding invariant points and invariant lines, and reading the determinant as an area or volume scale factor.

Generated by Claude Opus 4.812 min answer

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  1. What this dot point is asking
  2. Matrices as transformations and the column rule
  3. Standard transformations in two and three dimensions
  4. Composing transformations
  5. Invariant points and invariant lines
  6. The determinant as a scale factor
  7. Try this

What this dot point is asking

OCR wants you to read a matrix as a linear transformation: know the standard 2×22 \times 2 matrices for rotations, reflections, enlargements, stretches and shears (and the 3×33 \times 3 matrices for rotations and reflections in space), compose transformations by multiplying their matrices in the right order, find invariant points and invariant lines, and use the determinant as the area or volume scale factor.

Matrices as transformations and the column rule

A linear transformation fixes the origin and sends straight lines to straight lines. The key insight is that the columns of the matrix are the images of the standard basis vectors: the first column is where (10)\begin{pmatrix} 1 \\ 0 \end{pmatrix} goes, the second column where (01)\begin{pmatrix} 0 \\ 1 \end{pmatrix} goes. This lets you build a matrix from a described transformation, or read off a transformation from a matrix.

Standard transformations in two and three dimensions

Besides rotations and reflections, you should recognise a stretch parallel to an axis (for example (a001)\begin{pmatrix} a & 0 \\ 0 & 1 \end{pmatrix} stretches in the xx-direction by factor aa) and a shear (for example (1k01)\begin{pmatrix} 1 & k \\ 0 & 1 \end{pmatrix} shears parallel to the xx-axis). In three dimensions, rotations about a coordinate axis and reflections in a coordinate plane have 3×33 \times 3 matrices; for instance a rotation about the zz-axis keeps the zz-coordinate fixed and rotates the xx and yy coordinates.

Composing transformations

To apply transformation PP then transformation QQ to a point, you compute Q(Px)=(QP)x\mathbf{Q}(\mathbf{P}\mathbf{x}) = (\mathbf{Q}\mathbf{P})\mathbf{x}. The combined matrix is QP\mathbf{Q}\mathbf{P}, with the first transformation on the right. Order matters because matrix multiplication is not commutative.

Invariant points and invariant lines

An invariant point is fixed by the transformation: Mx=x\mathbf{M}\mathbf{x} = \mathbf{x}. For any transformation that fixes the origin, the origin itself is invariant; other invariant points satisfy (MI)x=0(\mathbf{M} - \mathbf{I})\mathbf{x} = \mathbf{0}. An invariant line is a line that maps onto itself (though individual points on it may move along it). To find invariant lines y=mxy = mx, apply M\mathbf{M} to a general point on the line and require the image to satisfy the same equation.

The determinant as a scale factor

The determinant of a transformation matrix is the factor by which it multiplies area (in two dimensions) or volume (in three). A determinant of 11 preserves area, a negative determinant reverses orientation (a reflection is present), and a zero determinant collapses the figure onto a line or plane, so the transformation cannot be undone.

Matrices as transformations connect to complex numbers, where multiplication by reiθr e^{i\theta} is exactly a rotation by θ\theta and an enlargement by rr.

Try this

Q1. Write the matrix for a reflection in the yy-axis. [1 mark]

  • Cue. The image of (10)\begin{pmatrix} 1 \\ 0 \end{pmatrix} is (10)\begin{pmatrix} -1 \\ 0 \end{pmatrix} and of (01)\begin{pmatrix} 0 \\ 1 \end{pmatrix} is itself: (1001)\begin{pmatrix} -1 & 0 \\ 0 & 1 \end{pmatrix}.

Q2. State the area scale factor of the transformation (3124)\begin{pmatrix} 3 & 1 \\ 2 & 4 \end{pmatrix}. [2 marks]

  • Cue. det=122=10|\det| = |12 - 2| = 10, so areas are multiplied by 1010.

Exam-style practice questions

Practice questions written in the style of OCR exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

OCR 20185 marksThe transformation TT is a rotation about the origin through 9090^\circ anticlockwise, followed by a reflection in the line y=xy = x. Find the single matrix representing TT and describe it as a single transformation.
Show worked answer →

Rotation 9090^\circ anticlockwise (M1): R=(0110)\mathbf{R} = \begin{pmatrix} 0 & -1 \\ 1 & 0 \end{pmatrix}. Reflection in y=xy = x (A1): F=(0110)\mathbf{F} = \begin{pmatrix} 0 & 1 \\ 1 & 0 \end{pmatrix}.

Apply the rotation first, so the reflection matrix is on the left (M1): T=FR=(0110)(0110)=(1001)T = \mathbf{F}\mathbf{R} = \begin{pmatrix} 0 & 1 \\ 1 & 0 \end{pmatrix}\begin{pmatrix} 0 & -1 \\ 1 & 0 \end{pmatrix} = \begin{pmatrix} 1 & 0 \\ 0 & -1 \end{pmatrix} (A1).

This is a reflection in the xx-axis (A1). Markers reward both correct matrices, multiplying in the right order (second transformation on the left), and identifying the resulting reflection.

OCR 20215 marksThe matrix M=(3011)\mathbf{M} = \begin{pmatrix} 3 & 0 \\ 1 & 1 \end{pmatrix} represents a transformation. Find the equations of any invariant lines of the form y=mxy = mx.
Show worked answer →

A point (x,mx)(x, mx) maps to a point still on y=mxy = mx. Apply M\mathbf{M} (M1): (3011)(xmx)=(3xx+mx)\begin{pmatrix} 3 & 0 \\ 1 & 1 \end{pmatrix}\begin{pmatrix} x \\ mx \end{pmatrix} = \begin{pmatrix} 3x \\ x + mx \end{pmatrix}.

For the image to lie on y=mxy = mx, its yy-coordinate must be mm times its xx-coordinate (M1): x+mx=m(3x)x + mx = m(3x), so 1+m=3m1 + m = 3m for all xx (A1).

Solve (M1): 1=2m1 = 2m, giving m=12m = \tfrac{1}{2} (A1).

So the invariant line is y=12xy = \tfrac{1}{2}x. Markers reward applying M\mathbf{M} to a general point, imposing that the image stays on the line, and solving for mm.

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