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How do levers and linkages change the size, direction or type of a force or motion?

Mechanisms based on levers and linkages: the three classes of lever, mechanical advantage and velocity ratio, the principle of moments applied to levers, and linkages (reverse motion, parallel motion, bell crank) that change the direction or type of motion.

A focused answer to OCR A-Level Product Design on mechanisms based on levers and linkages: the three classes of lever, mechanical advantage and velocity ratio with worked calculations, the principle of moments applied to levers, and the common linkages that change the direction or type of motion.

Generated by Claude Opus 4.812 min answer

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  1. What this dot point is asking
  2. The three classes of lever
  3. Mechanical advantage and velocity ratio
  4. The principle of moments applied to levers
  5. Linkages

What this dot point is asking

OCR wants you to know the three classes of lever, calculate mechanical advantage and velocity ratio, apply the principle of moments to levers, and describe the common linkages. Mechanisms change the size, direction or type of a force or motion, and they carry calculation marks.

The three classes of lever

The single most-tested point is identifying the class by which component is in the middle: fulcrum (first), load (second), effort (third).

Mechanical advantage and velocity ratio

The principle of moments applied to levers

Linkages

Exam-style practice questions

Practice questions written in the style of OCR exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

OCR 20194 marksA crowbar is used as a lever. The effort is applied 0.60 m from the pivot and the load sits 0.10 m from the pivot. Calculate the mechanical advantage and the effort needed to lift a 450 N load.
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A Component 01 lever calculation. Marks for the mechanical advantage, the method and the effort with units.

For an ideal lever, mechanical advantage equals the effort arm divided by the load arm: MA=0.600.10=6\text{MA} = \frac{0.60}{0.10} = 6. Using the principle of moments, effort×effort arm=load×load arm\text{effort} \times \text{effort arm} = \text{load} \times \text{load arm}, so effort=450×0.100.60=450.60=75\text{effort} = \frac{450 \times 0.10}{0.60} = \frac{45}{0.60} = 75 N. (Equivalently, effort = load divided by MA = 4506=75\frac{450}{6} = 75 N.)

A common dropped mark is inverting the mechanical advantage (load arm over effort arm) or omitting the unit; MA is effort arm over load arm, and a value above 1 means a small effort moves a large load.

OCR 20214 marksIdentify the class of lever for a pair of scissors and for a wheelbarrow, and explain the difference in where the fulcrum, effort and load lie.
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A Component 01 application question. Marks for each class and the explanation of the arrangement.

A pair of scissors is a first-class lever: the fulcrum (the pivot/rivet) is between the effort (the hand on the handles) and the load (the material being cut). A wheelbarrow is a second-class lever: the load (the contents) is between the fulcrum (the wheel) and the effort (the hands lifting the handles), which gives a large effort arm and a mechanical advantage greater than 1, so a small effort lifts a heavy load. The difference is the order: first class has the fulcrum in the middle; second class has the load in the middle (and third class has the effort in the middle, as in tweezers, favouring speed and range over force).

A common dropped mark is confusing second and third class; the middle component names the class only for first (fulcrum), and for second it is the load, for third the effort.

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