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How is mains AC turned into a smooth, regulated DC supply for an electronic system?

Mains power supply systems: the transformer, rectifier, reservoir smoothing and regulation stages, ripple voltage, and series and switch-mode regulators.

An Eduqas A-Level Electronics answer on mains power supply systems: the transformer that steps down mains voltage, the bridge rectifier, the reservoir capacitor and ripple, voltage regulation with a Zener or series regulator, and the efficiency advantage of a switch-mode supply.

Generated by Claude Opus 4.813 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this dot point is asking
  2. The answer
  3. Examples in context
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What this dot point is asking

Eduqas wants you to describe the stages of a mains power supply, the transformer, rectifier, reservoir smoothing and regulation, explain ripple voltage, and compare series (linear) and switch-mode regulators. This is the system that powers every other circuit in the course.

The answer

The transformer

Rectification and smoothing

Ripple voltage

Voltage regulation

Examples in context

Every plug-in adapter, phone charger and bench supply is a mains power supply of this kind. Cheap, low-power, low-noise supplies (such as for an audio pre-amplifier) often use a linear regulator; phone chargers and computer supplies use switch-mode designs for efficiency and small size. The ripple and regulation calculations decide the reservoir capacitor value and the regulator choice for a project in the non-exam assessment.

Try this

Q1. A transformer steps 230 V230\ \text{V} down to 9.0 V9.0\ \text{V}. Find the turns ratio. [2 marks]

  • Cue. NpNs=2309.0=26\frac{N_p}{N_s} = \frac{230}{9.0} = 26, about 26:126:1.

Q2. A secondary delivers 6.0 V6.0\ \text{V} RMS. Find the peak voltage the reservoir capacitor charges to. [2 marks]

  • Cue. Vpeak=6.0×2=8.5 VV_\text{peak} = 6.0 \times \sqrt 2 = 8.5\ \text{V}.

Q3. State one advantage of a switch-mode regulator over a linear regulator. [1 mark]

  • Cue. Much higher efficiency (it wastes little power, so it runs cool).

Exam-style practice questions

Practice questions written in the style of WJEC Eduqas exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Eduqas 20206 marksA mains power supply uses a transformer that steps 230 V230\ \text{V} RMS down to 12 V12\ \text{V} RMS, followed by a bridge rectifier and a reservoir capacitor. Calculate the transformer turns ratio and the approximate peak DC output voltage (ignoring diode drops). State one effect of increasing the load current on the ripple.
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Turns ratio (up to 2 marks): for an ideal transformer NpNs=VpVs=23012=19.2\dfrac{N_p}{N_s} = \dfrac{V_p}{V_s} = \dfrac{230}{12} = 19.2, so about 19:119:1.

Peak DC output (up to 2 marks): the reservoir capacitor charges to the peak of the secondary voltage, Vpeak=Vrms2=12×2=17 VV_\text{peak} = V_\text{rms}\sqrt{2} = 12 \times \sqrt 2 = 17\ \text{V} (a little less once diode drops are included).

Effect of load (up to 2 marks): a larger load current discharges the reservoir capacitor faster between peaks, so the ripple voltage increases (the output sags more before the next charging pulse).

Markers reward the turns ratio 19:119:1, the peak output 17 V17\ \text{V} from Vrms2V_\text{rms}\sqrt 2, and the statement that more load current means larger ripple.

Eduqas 20225 marksCompare a linear (series) regulator with a switch-mode regulator, giving one advantage of each.
Show worked answer →

Linear (series) regulator (up to 2 marks): it drops the excess voltage across a series transistor controlled by feedback, holding the output constant. Advantage: it is simple and produces a very clean, low-noise output with little electrical interference.

Switch-mode regulator (up to 2 marks): it rapidly switches the input on and off and uses an inductor and capacitor to store and average the energy, controlling the output by the switching duty cycle. Advantage: it is far more efficient (typically 85 to 95 per cent) because the switching transistor dissipates little, so it runs cool and suits high-power or battery use.

Conclusion (up to 1 mark): linear regulators are chosen for low noise and simplicity at low power; switch-mode regulators are chosen for efficiency at higher power.

Markers reward the series-pass versus switching mechanism, low noise as the linear advantage, and high efficiency as the switch-mode advantage.

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