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How do mass spectrometry and infrared spectroscopy help us identify organic molecules?

Mass spectrometry of organic compounds (molecular ion and fragmentation), infrared spectroscopy and characteristic absorptions, and using spectra to deduce structures and monitor functional groups.

An Eduqas A-Level Chemistry C3.5 answer on mass spectrometry of organic compounds (molecular ion and fragmentation) and infrared spectroscopy, and using spectra to deduce structures.

Generated by Claude Opus 4.810 min answer

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  1. What this topic is asking
  2. Mass spectrometry of organic molecules
  3. Infrared spectroscopy
  4. Using spectra together
  5. Examples in context
  6. Try this

What this topic is asking

Eduqas topic C3.5 introduces the two analytical techniques used at AS level: mass spectrometry applied to organic molecules (the molecular ion and fragmentation) and infrared spectroscopy (characteristic bond absorptions). You must use spectra to find relative molecular masses, identify fragments, recognise functional groups and deduce structures. The NMR and chromatography techniques are added in the Organic Chemistry and Analysis section.

Mass spectrometry of organic molecules

Common losses to memorise: 1515 (CH3\text{CH}_3), 1717 (OH\text{OH}), 1818 (water), 2929 (CHO\text{CHO} or C2H5\text{C}_2\text{H}_5) and 4545 (COOH\text{COOH}). An M+1\text{M}+1 peak arises from the small natural abundance of carbon-13.

Infrared spectroscopy

Covalent bonds absorb infrared radiation at characteristic frequencies, vibrating by stretching or bending. The wavenumber (in cm1\text{cm}^{-1}) of an absorption identifies the bond. Eduqas provides a data table; the key absorptions to recognise are the broad O-H of alcohols and acids, the sharp C=O of carbonyl compounds, and the N-H of amines.

Using spectra together

The strength of these techniques is combining them. The mass spectrum fixes the molecular mass and reveals fragments; the infrared spectrum identifies the functional groups present. Together they narrow many candidate structures to one, which is exactly the synoptic skill Component 3 rewards.

Examples in context

Example 1. Detecting drugs in sport. Mass spectrometry identifies banned substances from their molecular ion and characteristic fragmentation pattern, even at tiny concentrations, because the fragmentation acts as a chemical fingerprint.

Example 2. Monitoring a reaction by infrared. As a primary alcohol is oxidised to a carboxylic acid, the appearance of a strong C=O absorption near 1700 cm11700\ \text{cm}^{-1} confirms the reaction has occurred, letting chemists follow it without isolating the product.

Try this

Q1. In a mass spectrum, what does the molecular ion peak tell you? [1 mark]

  • Cue. Its m/zm/z value gives the relative molecular mass of the compound.

Q2. State the bond responsible for a strong absorption at about 1700 cm11700\ \text{cm}^{-1} in an infrared spectrum. [1 mark]

  • Cue. The carbonyl bond, C=O (found in aldehydes, ketones, carboxylic acids and esters).

Exam-style practice questions

Practice questions written in the style of WJEC Eduqas exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Eduqas 20194 marksThe mass spectrum of a compound shows a molecular ion peak at m/z=58m/z = 58 and a strong peak at m/z=43m/z = 43. (a) Suggest the relative molecular mass. (b) Suggest the identity of the fragment lost and the species responsible for the peak at 43, given the compound is a ketone.
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(a) The molecular ion peak gives the relative molecular mass directly: Mr=58M_r = 58 (1).

(b) The mass difference is 5843=1558 - 43 = 15, corresponding to loss of a methyl group (CH3\text{CH}_3) (1). The peak at m/z=43m/z = 43 is the acylium ion CH3CO+\text{CH}_3\text{CO}^+ (1). The compound is propanone, CH3COCH3\text{CH}_3\text{COCH}_3 (1).

Eduqas 20214 marksAn infrared spectrum of an organic compound shows a strong, broad absorption at about 3300 cm13300\ \text{cm}^{-1} and a strong absorption at about 1700 cm11700\ \text{cm}^{-1}. (a) Identify the bonds responsible. (b) Suggest, with reasons, which functional group is present if both absorptions appear together.
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(a) The broad absorption near 3300 cm13300\ \text{cm}^{-1} is the O-H bond; the absorption near 1700 cm11700\ \text{cm}^{-1} is the C=O bond (2).

(b) An O-H and a C=O together, with the O-H very broad (25002500 to 3300 cm13300\ \text{cm}^{-1}), indicate a carboxylic acid (-COOH\text{-COOH}), which contains both bonds (2).

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