Which chemical compounds build all living things, and how are they made, broken and tested for?
Biological compounds: the roles of water and inorganic ions; the structure of carbohydrates, lipids and proteins; condensation and hydrolysis; and the biochemical tests for these molecules.
A focused answer to the Eduqas Biology Core Concepts statement on biological compounds. Covers water and inorganic ions, the structure of carbohydrates, lipids and proteins, condensation and hydrolysis, and the biochemical food tests.
Reviewed by: AI editorial process; not yet individually human-reviewed
Have a quick question? Jump to the Q&A page
Jump to a section
What this dot point is asking
Eduqas wants you to know the biological roles of water and inorganic ions, the structures of carbohydrates, lipids and proteins, how monomers join by condensation and split by hydrolysis, and how to carry out and interpret the biochemical food tests. This is a Core Concepts statement, so it can appear on any of the three papers.
Water and inorganic ions
Water is a polar molecule: oxygen pulls the shared electrons more strongly than the hydrogens, so the oxygen is slightly negative () and the hydrogens slightly positive (). These partial charges let water molecules form hydrogen bonds with one another, which underlies almost every useful property Eduqas asks about.
Inorganic ions have specific roles: calcium ions () in bones, teeth and blood clotting; iron ions () at the centre of each haem group in haemoglobin, where oxygen binds; phosphate ions () in ATP, phospholipids and the backbone of nucleic acids; and hydrogen ions () in setting pH and in chemiosmosis during respiration and photosynthesis.
Carbohydrates
Carbohydrates contain only carbon, hydrogen and oxygen. Monosaccharides (glucose, in and forms, plus fructose and galactose) are the monomers. Two monosaccharides join by condensation to form a disaccharide and a glycosidic bond, releasing one water molecule (for example glucose plus fructose gives sucrose).
Polysaccharides are condensation polymers of many monosaccharides. Starch (amylose and amylopectin) is the plant energy store, compact and insoluble; glycogen is the more highly branched animal store, allowing fast hydrolysis when energy is needed; cellulose is structural, made of -glucose units that form straight chains held side by side by hydrogen bonds into strong microfibrils that give plant cell walls their tensile strength.
Lipids
Phospholipids have one fatty acid replaced by a phosphate group, giving a hydrophilic head and two hydrophobic tails. This is what makes them form a bilayer in water, the structural basis of every cell membrane. Triglycerides are excellent energy stores because they are compact, insoluble and release roughly twice the energy per gram of carbohydrate when respired.
Proteins
Proteins are polymers of amino acids joined by peptide bonds formed by condensation. There are four levels of structure: primary (the sequence of amino acids), secondary (the -helix and -pleated sheet held by hydrogen bonds along the backbone), tertiary (the overall 3D fold held by hydrogen, ionic and disulfide bonds between R groups), and quaternary (two or more polypeptide chains together, as in haemoglobin with its four chains and iron-containing haem groups). The precise tertiary shape is what gives enzymes and antibodies their specificity.
The biochemical tests
- Reducing sugars: add Benedict's reagent and heat in a water bath; a positive result turns from blue to brick-red.
- Non-reducing sugars: first hydrolyse with dilute acid, neutralise, then test with Benedict's; brick-red is positive.
- Starch: add iodine in potassium iodide solution; a positive result turns from orange-brown to blue-black.
- Proteins: add biuret reagent; a positive result turns from blue to lilac or purple.
- Lipids: the emulsion test, mix the sample with ethanol then add water; a positive result gives a cloudy white emulsion.
Examples in context
Example 1. Cellulose versus starch. Both are glucose polymers, yet cellulose is tough and structural while starch is a soft energy store. The difference is the isomer: -glucose in cellulose forces alternate units to flip, giving straight chains that hydrogen-bond into rigid microfibrils, whereas -glucose in starch coils into a compact, easily hydrolysed store. This is a classic Eduqas structure-and-function comparison.
Example 2. Haemoglobin and quaternary structure. Haemoglobin's four polypeptide chains, each holding an iron-containing haem group, let one molecule carry four oxygen molecules and show cooperative binding. This shows why quaternary structure matters: the assembled protein does something none of its single chains could, linking biological compounds directly to gas transport.
Try this
Q1. Name the bond formed when two monosaccharides join, and the reaction involved. [2 marks]
- Cue. Glycosidic bond, formed by condensation.
Q2. Explain why water is described as a good transport medium. [2 marks]
- Cue. It is polar, so it dissolves ions and polar solutes; it is a liquid that flows, carrying dissolved substances around the body.
Q3. Explain how the structure of cellulose makes it suited to its role in plant cell walls. [3 marks]
- Cue. Made of -glucose forming straight chains; chains held side by side by many hydrogen bonds into microfibrils; this gives high tensile strength to support the cell against turgor pressure.
Exam-style practice questions
Practice questions written in the style of WJEC Eduqas exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.
Eduqas 20194 marksDescribe how a triglyceride is formed from glycerol and fatty acids, and name the type of bond and reaction involved.Show worked answer →
A triglyceride forms when one glycerol molecule joins to three fatty acids.
Each fatty acid bonds to glycerol by a condensation reaction, forming an ester bond between the carboxyl group of the fatty acid and a hydroxyl group of glycerol.
Three condensation reactions occur, so three molecules of water are released in total.
Markers reward the ester bond, the condensation reaction, and the loss of three water molecules.
Eduqas 20215 marksOutline how you would test a food sample for reducing sugar, non-reducing sugar, starch and protein, stating the positive result in each case, and explain why the non-reducing sugar test needs an extra step.Show worked answer →
Reducing sugar: add Benedict's reagent and heat in a water bath; a positive result changes from blue to brick-red.
Non-reducing sugar: first boil a fresh sample with dilute hydrochloric acid (to hydrolyse it into reducing monosaccharides), neutralise with sodium hydrogencarbonate, then carry out the Benedict's test; brick-red is positive.
Starch: add iodine in potassium iodide solution; orange-brown changes to blue-black.
Protein: add biuret reagent; blue changes to lilac or purple.
The extra acid step is needed because a non-reducing sugar such as sucrose cannot reduce Benedict's reagent until it is hydrolysed into its reducing monosaccharide units.
Markers reward the correct reagents, the correct positive colours, and the reason for hydrolysing the non-reducing sugar first.
Related dot points
- Cell structure and organisation: the ultrastructure and functions of eukaryotic organelles; the differences between prokaryotic and eukaryotic cells; microscopy and magnification; and the organisation of cells into tissues, organs and systems.
A focused answer to the Eduqas Biology Core Concepts statement on cell structure. Covers eukaryotic organelles and the secretory pathway, prokaryotic cells, microscopy and resolution, magnification calculations, and the organisation of cells into tissues and organs.
- Cell membranes and transport: the fluid-mosaic model; diffusion and facilitated diffusion; osmosis and water potential; active transport; bulk transport by endocytosis and exocytosis; and the factors affecting the rate of movement.
A focused answer to the Eduqas Biology Core Concepts statement on membranes. Covers the fluid-mosaic model, simple and facilitated diffusion, osmosis and water potential, active transport, endocytosis and exocytosis, and the factors that affect the rate of transport.
- Enzymes: their role as biological catalysts; the lock-and-key and induced-fit models; the formation of enzyme-substrate complexes; the effects of temperature, pH, substrate concentration and enzyme concentration; and competitive and non-competitive inhibition.
A focused answer to the Eduqas Biology Core Concepts statement on enzymes. Covers enzymes as catalysts, the lock-and-key and induced-fit models, the four rate factors, denaturation, and competitive and non-competitive inhibition.
- Nucleic acids and protein synthesis: the structure of DNA and RNA; semi-conservative replication; the genetic code; transcription and translation; and the role of ATP.
A focused answer to the Eduqas Biology Core Concepts statement on nucleic acids. Covers the structure of DNA and RNA, semi-conservative replication, the genetic code, transcription and translation, and the role of ATP.
- Cell division: the cell cycle and its control; mitosis and its role in growth and repair; meiosis and the production of genetic variation; and the mitotic index.
A focused answer to the Eduqas Biology Core Concepts statement on cell division. Covers the cell cycle and its checkpoints, the stages of mitosis, meiosis and the sources of variation it creates, and the mitotic index calculation.
Sources & how we know this
- Eduqas A Level Biology Specification (A400) — Eduqas (2015)