How do forces determine how objects move?
Scalars and vectors, resolving and combining forces, free-body diagrams, Newton's three laws of motion, weight, friction and the conditions for equilibrium and moments.
A focused answer to the Edexcel 9PH0 forces content, covering scalars and vectors, resolving and combining forces, free-body diagrams, Newton's three laws, weight, friction, and the conditions for equilibrium and moments.
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What this dot point is asking
Edexcel wants you to distinguish scalars from vectors, resolve and combine forces, draw free-body diagrams, state and apply Newton's three laws, work with weight and friction, and use the conditions for equilibrium including the principle of moments.
The answer
Scalars, vectors and resolving
To add vectors, either draw them tip-to-tail and measure the resultant, or resolve each into components, add the components separately, and recombine using Pythagoras and trigonometry. Resolving is the workhorse of mechanics: choose convenient axes (often along and perpendicular to an incline) so that one component lines up with the motion.
Newton's three laws
The second law is the key calculating tool: find the resultant force, then . The third law explains rocket propulsion, walking, and why a book on a table is not the same Newton pair as the table pushing the book up (that is the normal contact pair with the book pushing down on the table).
Weight, friction and free-body diagrams
Weight is the gravitational force , acting from the centre of mass. Friction opposes relative sliding and depends on the surfaces and the normal contact force, not on the contact area. A free-body diagram shows one chosen body with every force acting on it (weight, normal contact force, tension, friction, applied force) drawn as arrows from the body; it is the essential first step before resolving and applying .
Equilibrium and moments
For a body in equilibrium under three forces, the three force vectors form a closed triangle. Choosing to take moments about the point where an unknown force acts eliminates that force from the equation, simplifying the algebra.
Examples in context
A climber's rope tension and the normal force from the rock are resolved to check equilibrium on a slope. A crane's jib is analysed with moments to keep the load balanced about the pivot. Seat belts and crumple zones apply Newton's second law in the momentum form to reduce the force during a crash. A rocket rises by Newton's third law, expelling exhaust gas backwards so the gas pushes the rocket forwards. A ladder against a wall is a classic three-force equilibrium-and-moments problem.
Try this
Q1. State Newton's second law in its momentum form. [1 mark]
- Cue. The resultant force equals the rate of change of momentum, .
Q2. A force of N acts at degrees to the horizontal. Find its horizontal component. [2 marks]
- Cue. N.
Q3. A m spanner needs a moment of N m to loosen a bolt. Find the perpendicular force required at the end. [2 marks]
- Cue. N.
Exam-style practice questions
Practice questions written in the style of Pearson Edexcel exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.
Edexcel 20174 marksA box of mass kg is pulled along a rough horizontal floor by a rope at degrees above the horizontal with a tension of N. The box accelerates at m per second squared. Calculate the frictional force on the box.Show worked answer →
Resolve the tension horizontally: N.
Apply Newton's second law horizontally: N.
So N.
Markers reward resolving the tension, applying to the horizontal direction, and the value about N.
Edexcel 20204 marksA uniform beam of weight N and length m rests on a pivot m from one end. A N weight hangs from that nearer end. Calculate the force needed at the far end to balance the beam.Show worked answer →
Take moments about the pivot. The beam's weight acts at its centre, m on the far side of the pivot; the N hangs m on the near side; the unknown force acts m from the pivot on the far side.
Clockwise (far side) moments: . Anticlockwise (near side): .
For equilibrium: , so , giving N.
Markers reward taking moments about the pivot, including the beam's weight at its centre, and the value about N.
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Sources & how we know this
- Pearson Edexcel A-Level Physics (9PH0) specification — Pearson Edexcel (2015)