How do you reverse differentiation to find areas, volumes and total change?
Indefinite and definite integrals, areas under curves, integrals of standard functions, integration by substitution and by parts, integration using partial fractions, and differential equations.
A focused answer to the Edexcel A-Level Mathematics integration content, covering indefinite and definite integrals, areas under curves, standard integrals, integration by substitution and by parts, integration with partial fractions, and solving differential equations.
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What this dot point is asking
Edexcel wants you to integrate standard functions, find indefinite and definite integrals, calculate areas under and between curves, integrate by substitution and by parts, use partial fractions to integrate rational functions, and solve first-order differential equations by separating variables.
The answer
Indefinite and definite integrals
Standard integrals include , , and .
Substitution and by parts
Substitution reverses the chain rule: replace part of the integrand with and convert using . The aim is to choose so that the integral becomes a standard one in . For a definite integral you also change the limits into -values, which saves converting back to at the end.
Integration using partial fractions
A rational function whose denominator factorises can be split into simpler fractions, each of which integrates to a logarithm. This is the standard route for integrands such as .
Areas
The area between a curve and the -axis is . Where the curve dips below the axis the integral is negative, so split the region at the roots and add the magnitudes. The area between two curves and with is .
Differential equations
A separable equation is solved by writing and integrating each side, then using a boundary condition to find the constant. Such equations model situations where the rate of change depends on the current value, such as cooling, population growth and the discharge of a capacitor.
Examples in context
Try this
Q1. Find . [2 marks]
- Cue. .
Q2. Evaluate . [3 marks]
- Cue. .
Exam-style practice questions
Practice questions written in the style of Pearson Edexcel exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.
Edexcel 20186 marksThe region is bounded by the curve and the -axis. Find the area of .Show worked answer →
Find where the curve meets the -axis: , so , giving and (M1, A1).
Between and the curve is below the axis, so the integral is negative and the area is its magnitude. Integrate (M1): (A1).
At : . At : . The integral is (M1).
The area is square units (A1).
Markers reward the roots, integrating correctly, evaluating at the limits, and taking the magnitude for area.
Edexcel 20215 marksUse integration by parts to find .Show worked answer →
Choose (simplifies on differentiating) and (M1), so and (A1).
Apply the formula (M1):
(A1).
Integrate the remaining term: (A1).
Markers reward a sensible choice of and , applying the by-parts formula, and the constant of integration.
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Sources & how we know this
- Pearson Edexcel A-Level Mathematics (9MA0) specification — Pearson Edexcel (2017)