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How do matrices encode linear transformations and systems of equations, and how do you invert them?

Matrix arithmetic, determinants, inverses of 2x2 and 3x3 matrices, matrices as linear transformations, invariant points and lines, and solving linear systems.

A focused answer to the Edexcel A-Level Further Mathematics matrices content, covering matrix arithmetic, determinants, inverses of 2x2 and 3x3 matrices, matrices as linear transformations, invariant points and lines, and using the inverse to solve systems of linear equations.

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  1. What this dot point is asking
  2. Arithmetic and determinants
  3. Inverting a 3x3 matrix
  4. Matrices as transformations
  5. Solving linear systems
  6. Examples in context
  7. Try this

What this dot point is asking

Edexcel wants you to add, subtract and multiply matrices, evaluate 2×22 \times 2 and 3×33 \times 3 determinants, find inverses, interpret matrices as linear transformations of the plane and of space, find invariant points and invariant lines, and use the inverse matrix to solve simultaneous equations. Matrices are a guaranteed Core Pure topic and frequently combine with transformation geometry and, in the 3×33 \times 3 case, with solving systems of three equations.

Arithmetic and determinants

Matrix addition is component-wise and only defined for matrices of the same size. Multiplication combines each row of the first matrix with each column of the second, so ABAB is defined only when the number of columns of AA equals the number of rows of BB. The (i,j)(i, j) entry of ABAB is the dot product of row ii of AA with column jj of BB. Order matters: ABAB and BABA are usually different and may not even both exist.

The determinant is the single most important number attached to a square matrix because it decides invertibility and gives the area (or volume) scale factor of the transformation.

A matrix with detA=0\det A = 0 is called singular and has no inverse; geometrically it collapses the plane onto a line (or space onto a plane), losing a dimension.

Inverting a 3x3 matrix

To invert a non-singular 3×33 \times 3 matrix, follow four steps: find the determinant; build the matrix of minors (each entry is the 2×22 \times 2 determinant left after deleting that entry's row and column); apply the chequerboard sign pattern (+++++)\begin{pmatrix} + & - & + \\ - & + & - \\ + & - & + \end{pmatrix} to get the cofactor matrix; transpose to get the adjugate; then divide by the determinant.

Matrices as transformations

A 2×22 \times 2 matrix maps the plane linearly, fixing the origin. The columns are the images of the basis vectors (10)\begin{pmatrix} 1 \\ 0 \end{pmatrix} and (01)\begin{pmatrix} 0 \\ 1 \end{pmatrix}, so you can read a transformation straight off the matrix. Standard cases are the rotation through θ\theta anticlockwise about the origin, (cosθsinθsinθcosθ)\begin{pmatrix} \cos\theta & -\sin\theta \\ \sin\theta & \cos\theta \end{pmatrix}; the reflection in the line y=xtanθy = x\tan\theta; and the enlargement by scale factor kk, (k00k)\begin{pmatrix} k & 0 \\ 0 & k \end{pmatrix}. A composition of transformations is the product of their matrices, applied right to left, so "first PP then QQ" is the matrix QPQP.

To find invariant points, solve (AI)x=0(A - I)\mathbf{x} = \mathbf{0}. To find invariant lines y=mx+cy = mx + c, demand that the image of a general point on the line also satisfies the same line equation, then equate gradients and intercepts.

Solving linear systems

A system written as Ax=bA\mathbf{x} = \mathbf{b} has the unique solution x=A1b\mathbf{x} = A^{-1}\mathbf{b} when detA0\det A \neq 0. When detA=0\det A = 0 the system is either inconsistent (no solution, parallel planes) or has infinitely many solutions (a line or plane of solutions), so you must check by substitution rather than assume one or the other. For three equations in three unknowns, the geometry of the three planes (meeting at a point, in a line, or not at all) mirrors these algebraic cases.

Examples in context

Matrices reach across the whole Further Maths course. The determinant as an area scale factor links to integration and to the Jacobian idea in change of variables. Eigenvalues and eigenvectors (the natural sequel) decide invariant lines through the origin and diagonalise a matrix, and the eigenvalues of a rotation matrix are the complex conjugates cosθ±isinθ\cos\theta \pm i\sin\theta, tying matrices to complex numbers. In mechanics, transformation matrices model rigid rotations of frames. The inverse-matrix method for systems generalises to the 3×33 \times 3 case that appears in coordinate-geometry questions about intersecting planes, and proof by induction is the standard tool for establishing a formula for AnA^n once you have spotted the pattern in the first few powers.

Try this

Q1. Find the determinant of (5234)\begin{pmatrix} 5 & 2 \\ 3 & 4 \end{pmatrix} and state whether it is invertible. [2 marks]

  • Cue. det=206=140\det = 20 - 6 = 14 \neq 0, so it is invertible.

Q2. Solve (2113)(xy)=(55)\begin{pmatrix} 2 & 1 \\ 1 & 3 \end{pmatrix}\begin{pmatrix} x \\ y \end{pmatrix} = \begin{pmatrix} 5 \\ 5 \end{pmatrix} using the inverse. [4 marks]

  • Cue. det=5\det = 5, inverse 15(3112)\frac{1}{5}\begin{pmatrix} 3 & -1 \\ -1 & 2 \end{pmatrix}, giving x=2x = 2, y=1y = 1.

Q3. The matrix (1301)\begin{pmatrix} 1 & 3 \\ 0 & 1 \end{pmatrix} represents a shear. Find its invariant points. [3 marks]

  • Cue. Solve (AI)x=0(A - I)\mathbf{x} = \mathbf{0}: (0300)x=0\begin{pmatrix} 0 & 3 \\ 0 & 0 \end{pmatrix}\mathbf{x} = \mathbf{0} gives y=0y = 0, so the xx-axis is the line of invariant points.

Exam-style practice questions

Practice questions written in the style of Pearson Edexcel exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Edexcel 20186 marksThe matrix A=(2134)A = \begin{pmatrix} 2 & -1 \\ 3 & 4 \end{pmatrix}. Find detA\det A and hence find A1A^{-1}. Use your answer to solve the simultaneous equations 2xy=42x - y = 4 and 3x+4y=53x + 4y = 5.
Show worked answer →

Compute the determinant, write the inverse, then apply it to the right-hand side vector.

detA=(2)(4)(1)(3)=8+3=11\det A = (2)(4) - (-1)(3) = 8 + 3 = 11 (M1 A1).

A1=111(4132)A^{-1} = \frac{1}{11}\begin{pmatrix} 4 & 1 \\ -3 & 2 \end{pmatrix} (M1 A1 for swapping leading diagonal and negating the off-diagonal).

Then (xy)=A1(45)=111(16+512+10)=111(212)\begin{pmatrix} x \\ y \end{pmatrix} = A^{-1}\begin{pmatrix} 4 \\ 5 \end{pmatrix} = \frac{1}{11}\begin{pmatrix} 16 + 5 \\ -12 + 10 \end{pmatrix} = \frac{1}{11}\begin{pmatrix} 21 \\ -2 \end{pmatrix} (M1), so x=2111x = \frac{21}{11}, y=211y = -\frac{2}{11} (A1).

Edexcel 20207 marksThe matrix M=(120013201)M = \begin{pmatrix} 1 & 2 & 0 \\ 0 & 1 & 3 \\ 2 & 0 & 1 \end{pmatrix}. Show that detM=13\det M = 13 and hence determine whether MM is invertible.
Show worked answer →

Expand the determinant along the top row using the cofactor signs.

detM=1130120321+0\det M = 1\begin{vmatrix} 1 & 3 \\ 0 & 1 \end{vmatrix} - 2\begin{vmatrix} 0 & 3 \\ 2 & 1 \end{vmatrix} + 0 (M1 for the expansion with correct signs).

The minors are 1301=1\begin{vmatrix} 1 & 3 \\ 0 & 1 \end{vmatrix} = 1 and 0321=06=6\begin{vmatrix} 0 & 3 \\ 2 & 1 \end{vmatrix} = 0 - 6 = -6 (A1 A1).

So detM=1(1)2(6)+0=1+12=13\det M = 1(1) - 2(-6) + 0 = 1 + 12 = 13 (A1). Since detM=130\det M = 13 \neq 0, MM is non-singular and therefore invertible (B1 for the conclusion, M1 A1 for full method).

Edexcel 20225 marksA transformation of the plane is represented by T=(3011)T = \begin{pmatrix} 3 & 0 \\ 1 & 1 \end{pmatrix}. Find the equation of the line of invariant points, or show that the origin is the only invariant point.
Show worked answer →

Invariant points satisfy Tx=xT\mathbf{x} = \mathbf{x}, so solve (TI)x=0(T - I)\mathbf{x} = \mathbf{0}.

TI=(2010)T - I = \begin{pmatrix} 2 & 0 \\ 1 & 0 \end{pmatrix} (M1). The equations are 2x=02x = 0 and x+0y=0x + 0y = 0, i.e. x=0x = 0 from both (A1).

So every point with x=0x = 0 is invariant: the line of invariant points is the yy-axis, x=0x = 0 (A1 A1). Because det(TI)=0\det(T - I) = 0 there is a whole line of fixed points rather than just the origin (B1 for noting the determinant is zero).

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