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How do the lever systems of the body and the factors affecting projectiles influence performance?

The three classes of lever and their mechanical advantage, the analysis of angular motion including moment of inertia and angular momentum, and the factors affecting the horizontal and vertical components of projectile motion.

A focused answer to AQA A-Level PE biomechanics on levers and projectile motion, covering the three classes of lever and mechanical advantage, angular motion, moment of inertia and angular momentum, and the factors affecting projectile flight.

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  1. What this dot point is asking
  2. Lever systems
  3. Angular motion
  4. Projectile motion

What this dot point is asking

AQA wants you to identify the three classes of lever in the body, work out their mechanical advantage, analyse angular motion using moment of inertia and angular momentum, and explain the factors that affect the horizontal and vertical components of a projectile's flight path.

Lever systems

A reliable way to remember the order is the mnemonic for what sits in the middle, 1-2-3 = F-L-E: first class has the Fulcrum in the middle, second class the Load, third class the Effort. Because most body levers are third class, the body is built for large, fast ranges of movement at the cost of mechanical advantage, which is why muscles must generate large forces to move comparatively light loads quickly.

Angular motion

Angular motion is rotation about an axis. The moment of inertia (II) is the resistance of a body to a change in its state of rotation; it increases when mass is spread further from the axis. Angular velocity (ω\omega) is the rate of rotation, and angular momentum is L=IωL = I\omega.

Because there is no external rotational force in the air, angular momentum is conserved. A trampolinist who tucks moves mass closer to the axis, reducing II, so ω\omega increases and they spin faster; opening out raises II and slows the spin to control the landing.

Projectile motion

A projectile (a thrown or struck object, or the body in flight) follows a parabolic path. Its motion has two independent components:

  • The horizontal component of velocity stays constant (ignoring air resistance), so it determines the distance.
  • The vertical component is changed by gravity, decreasing on the way up and increasing on the way down.

The flight path and distance depend on three release factors: the angle of release (around 45 degrees for maximum range when release and landing heights are equal), the speed (velocity) of release and the height of release. For shorter, faster events such as a shot put, the optimum angle is below 45 degrees (typically 38 to 42 degrees) because the release height is above the landing height, which gives extra flight time.

AQA also expects you to interpret the parabola of flight in terms of the two forces acting once an object is airborne (ignoring air resistance): weight acts vertically down throughout, while there is no horizontal force, so the horizontal velocity is constant and only the vertical velocity changes. When weight is the dominant or only force, the path is a true symmetrical parabola. For light objects with a large surface area, such as a shuttlecock or a discus, air resistance is significant and distorts the path into an asymmetric curve, with the descent steeper than the ascent. Drawing the resultant force, the horizontal and vertical components, and the parabolic path is a common diagram question.

Exam-style practice questions

Practice questions written in the style of AQA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

AQA 20203 marksA second-class lever has an effort arm of 20 cm and a load arm of 5 cm. Calculate its mechanical advantage and state what this tells you about the lever.
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Worked calculation. Mechanical advantage is the ratio of the effort arm to the load arm: MA=effort armload arm=205=4\text{MA} = \dfrac{\text{effort arm}}{\text{load arm}} = \dfrac{20}{5} = 4 (1 mark formula, 1 mark answer). Interpretation: a mechanical advantage greater than 1 means a relatively small effort can move a large load, which is the characteristic of a second-class lever such as the body rising onto the toes at the ankle (1 mark). Reward the correct value (no units, as it is a ratio) and the link to the load arm being shorter than the effort arm.

AQA 20184 marksExplain, using the conservation of angular momentum, how a figure skater controls the speed of a spin.
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AO1/AO2. Angular momentum is the product of moment of inertia and angular velocity, L=IωL = I\omega, and in the absence of an external turning force it is conserved (stays constant). To spin faster, the skater pulls the arms and one leg in towards the axis of rotation, concentrating mass close to the axis and reducing the moment of inertia II. Because LL is constant, a smaller II must be matched by a larger angular velocity ω\omega, so the skater spins faster. To slow down before stopping, the skater extends the arms and leg outwards, increasing II and so decreasing ω\omega. Full marks need the conservation statement plus the inverse relationship between II and ω\omega applied to both speeding up and slowing down.

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