How do forces determine the motion of an object, and how do you apply Newton's laws to solve problems?
Force as a vector, the resultant of forces, Newton's three laws of motion, weight and the relationship between mass and weight, connected particles, and resolving forces in two dimensions.
A focused answer to the AQA A-Level Mathematics forces content, covering force as a vector, resultant forces, Newton's three laws, weight, connected particles, and resolving forces in two dimensions.
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What this dot point is asking
AQA wants you to treat force as a vector, find resultant forces, apply Newton's three laws, relate mass and weight, solve problems involving connected particles, and resolve forces into components in two dimensions. This is the heart of mechanics: almost every problem reduces to drawing a force diagram and applying in chosen directions.
Force as a vector and the resultant
Forces add as vectors. If several forces act on a body, the resultant is their vector sum, found by adding components in two perpendicular directions. A body is in equilibrium precisely when the resultant force is zero, which means the components in each direction separately sum to zero. Drawing a clear force diagram, with weight, normal reaction, tension, friction and any applied force, is the essential first step and is often worth marks in its own right.
Newton's laws
Newton's first law is the special case of the second with zero resultant force, giving equilibrium (rest or constant velocity). Newton's third law says that if body A exerts a force on body B, then B exerts an equal and opposite force on A. The key point for exams is that these two forces act on different bodies, so they never cancel when you analyse a single body.
Resolving forces in two dimensions
In two dimensions you resolve each force into perpendicular components, usually horizontal and vertical, or along and perpendicular to a slope, then apply in each direction independently. A force at angle to a chosen axis has component along that axis and perpendicular to it. On an inclined plane it is almost always easier to resolve along and perpendicular to the slope than horizontally and vertically.
Connected particles
The light string assumption means its mass is negligible (so tension is uniform), and inextensible means the connected particles share one acceleration. For a system on a table with a hanging mass, the hanging mass drives the motion; for two hanging masses, the heavier one descends.
Exam-style practice questions
Practice questions written in the style of AQA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.
AQA 20187 marksPaper 2, Section B. Two particles of mass kg and of mass kg are connected by a light inextensible string passing over a smooth pulley at the edge of a smooth horizontal table. rests on the table and hangs vertically. The system is released from rest. Take metres per second squared. (a) Find the acceleration of the system. (b) Find the tension in the string.Show worked answer →
Let the acceleration be and the tension . For the hanging particle (taking downward as positive): . For on the smooth table (horizontal): . Adding the two equations eliminates : , so metres per second squared. Then newtons. Markers reward applying separately to each particle with the shared acceleration and common tension, and eliminating to solve.
AQA 20215 marksPaper 2, Section A. A block of mass kg rests on a smooth plane inclined at degrees to the horizontal. It is held in equilibrium by a force acting up the line of greatest slope. Take metres per second squared. (a) By resolving along the slope, find . (b) Find the normal reaction between the block and the plane.Show worked answer →
Resolve along the slope. The component of weight down the slope is . For equilibrium, newtons. Resolve perpendicular to the slope: the normal reaction balances the perpendicular weight component, newtons. Markers reward correct resolution into components parallel and perpendicular to the slope, with used for the along-slope component and for the normal reaction.
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Sources & how we know this
- AQA A-level Mathematics (7357) specification — AQA (2017)